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Nikolay [14]
2 years ago
11

√x + 2√b What’s the conjugate?

Mathematics
1 answer:
MakcuM [25]2 years ago
8 0

Answer: -2\sqrt{b}

Step-by-step explanation:

the conjugate is:

-2\sqrt{b}

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What are the factors of x^2 + 3x -4 ?​
algol13

Answer:

1 and -4

Step-by-step explanation:

cause when you factor the equation its (x-1)(x+4)

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Please ASAP.<br> Find the value of u.
shusha [124]

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The answer is B 62

Step-by-step explanation:

I just divid 124 by 2

5 0
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How to write 24.58 form?<br><br> I got something different is this right or wrong.
Vika [28.1K]

Answer:

That is correct.

Step-by-step explanation:

2 times 10=20

4 times 1=4

5 times 0.1=0.5

8 times 0.01=0.08

20+4+0.5+0.08=24.58

That is correct.

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What is 3515- x = 1396
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Step-by-step explanation:

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3 years ago
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The television show CSI: Shoboygan has been successful for many years. That show recently had a share of 18, meaning that among
jeyben [28]

Answer:

(a) The value of P (None) is 0.062.

(b) The value of P(at least one) is 0.938.

(c) The value of P(at most one) is 0.253.

(d) The event is not unusual.

Step-by-step explanation:

Let <em>X</em> = number of households watching the show.

The probability of the random variable <em>x</em> is, P (X) = <em>p</em> = 0.18.

The sample selected for the survey is of size, <em>n</em> = 14

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 14 and <em>p</em> = 0.18.

The probability of a Binomial distribution is computed using the formula:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,...

(a)

Compute the probability that none of the households are tuned to CSI: Shoboygan as follows:

P(X=0)={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}=1\times1\times0.06214=0.062

Thus, the value of P (None) is 0.062.

(b)

Compute the probability that at least one household is tuned to CSI: Shoboygan as follows:

P (X ≥ 1) = 1 - P (X < 1)

             = 1 - P (X = 0)

             =1-0.062\\=0.938

Thus, the value of P(at least one) is 0.938.

(c)

Compute the probability that at most one household is tuned to CSI: Shoboygan as follows:

P (X ≤ 1) = P (X = 0) + P (X = 1)

             ={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}+{14\choose 1}(0.18)^{1}(1-0.18)^{14-1}\\=0.062+0.191\\=0.253

Thus, the value of P(at most one) is 0.253.

(d)

An event that has a very low probability of occurrence is known as an unusual event.

The probability of the event "at most one household is tuned to CSI: Shoboygan" is 0.253.

This probability value is not low.

Hence, the event is not unusual.

5 0
4 years ago
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