Question

Have you ever been on or seen a ride like this at a fair or amusement park? Imagine being strapped into your seat at the bottom of this 350-foot tower, with your feet dangling just above the ground. You make the trip up the tower at a steady rate of 20 feet per second, stop at the top of the tower to hang for a few seconds, then suddenly drop in a free fall for 288 feet!
The trip up the tower is a linear relationship. The height of the riders, h, is equal to the constant rate multiplied by the time, t, since they began the trip up.

The free fall down the tower is a quadratic relationship. The distance from the top to the bottom of the free fall, d, is modeled by this equation, where t is the time since the free fall began and is the initial distance above the bottom of the free fall.
Write an equation representing each relationship.

Enter the correct answer in the box.

Answer 1

The linear relationship is y = 20x, 0 ≤ x ≤ 17.5 and the quadratic relationship is y = -16x² + 288, 0 ≤ x ≤ 3√2

The equations that represent the relationships

The linear relationship

When making the trip up, we have:

Rate = 20 feet per seconds

This means that the relationship is:

Distance = Rate * Time

So, we have:

y = 20x

The height of the tower is 350.

So, we have:

20x = 350

Divide by 20

x = 17.5

Hence, the linear relationship is y = 20x, 0 ≤ x ≤ 17.5

The quadratic relationship

The quadratic equation can be represented as:

y = -0.5ax² + vx + h

Where:

• a = acceleration due to gravity = 32
• v = velocity = 0
• h = height = 288

So, we have:

y = -0.5 * 32x² + 0 * x + 288

Evaluate

y = -16x² + 288

When you get to the ground level, we have:

-16x² + 288 = 0

Subtract 288 from both sides

-16x² = -288

Divide by -16

x² = 18

Take the square root of both sides

x = ±3√2

Remove negative domain

x = 3√2

Hence, the quadratic relationship is y = -16x² + 288, 0 ≤ x ≤ 3√2

Read more about linear and quadratic equations at:

brainly.com/question/72196

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