<span>the reduced price is represented by: x-(.14*x)</span>
We have that
<span>A' (2,1)
C(-2,2)-------> </span>Using the transformation-----> C' (-2+2,2+1)----> C' (0,3)
with
A' (2,1) and C' (0,3)
find the distance <span>C'A'
d=</span>√[(y2-y1)²+(x2-x1)²]----> d=√[(3-1)²+(0-2)²]----> d=√8----> 2√2 units
the answer is
the distance C'A' is 2√2 units
So far the answer is 0.7958800173440752 good job for me right
Answer:
(4t - 8/5) - (3 - 4/3t) = 16/3t - 23/5
5(2t + 1) + (-7t + 28)= 3t+33
(-9/2t +3) + (7/4t + 33) = -11/4c+56
3 (3t-4) - (2t + 10)= 7t -22
Sooo Sorry that it took soooo long! Hope this helps!!!
Happy holidays!!
The angles of an equilateral triangle are always 60°
