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mel-nik [20]
2 years ago
6

Please help! I am stuck on this

Mathematics
1 answer:
DaniilM [7]2 years ago
7 0

Answer:

c.

Step-by-step explanation:

Assuming we are not restricting the domain of f, the inverse isn't a function

\frac{1}{ {x}^{2} }  - 7

y =  \frac{1}{ {x}^{2} }  - 7

x =  \frac{1}{ {y}^{2} }  - 7

x + 7 =  \frac{1}{ {y}^{2} }

{y}^{2}  =  \frac{1}{x + 7}

y =  \sqrt{ \frac{1}{x + 7} }

Since square root are Positve or negative, the function will not be a function.

The correct answer is c.

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Assume that the weight loss for the first month of a diet program varies between 6 pounds and 12 pounds, and is
swat32

Answer:

1/3

Step-by-step explanation:

Range of data set: 12 - 6 = 6

Given that there is a uniform distribution:

P(6<x<7) = 1/6

P(7<x<8) = 1/6

P(8<x<9) = 1/6

P(9<x<10) = 1/6

P(10<x<11) = 1/6

P(11<x<12) = 1/6

where x is weight loss

Probability that weight loss is more than 10 pounds:

P(10<x<11) + P(11<x<12) = 1/6 + 1/6 = 1/3

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3 years ago
PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU B
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Answer:

x = -10

y = -13

Step-by-step explanation:

-6(y + 3) + 4y = 8

-6y - 18 + 4y = 8

-2y - 18 = 8

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-2y (÷ -2) = 26 (÷ -2)

y = -13

x = -13 + 3

x = -10

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2 years ago
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X and Y

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Given g of x equals cube root of the quantity x minus 3, on what interval is the function positive?
zmey [24]

The function is positive when x is larger than 3, then the interval in where the function is positive is: (3, ∞)

<h3>on what interval is the function positive?</h3>

The function is positive when g(x) > 0.

Then we need to solve:

∛(x - 3) > 0

We can directly remove the cubic root, because it does not affect the sign of the argument, then:

x - 3 > 0

x > 3

The function is positive when x is larger than 3, then the interval in where the function is positive is: (3, ∞)

If you want to learn more about functions:

brainly.com/question/2456547

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