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mel-nik [20]
2 years ago
6

Please help! I am stuck on this

Mathematics
1 answer:
DaniilM [7]2 years ago
7 0

Answer:

c.

Step-by-step explanation:

Assuming we are not restricting the domain of f, the inverse isn't a function

\frac{1}{ {x}^{2} }  - 7

y =  \frac{1}{ {x}^{2} }  - 7

x =  \frac{1}{ {y}^{2} }  - 7

x + 7 =  \frac{1}{ {y}^{2} }

{y}^{2}  =  \frac{1}{x + 7}

y =  \sqrt{ \frac{1}{x + 7} }

Since square root are Positve or negative, the function will not be a function.

The correct answer is c.

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2 years ago
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