I'm sorry the picture is blurry. Could you post another one.
<u>ANSWER: </u>
x-intercepts of 
<u>SOLUTION:</u>
Given,
-- eqn 1
x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.
Now, let us find the zeroes using quadratic formula for f(x) = 0.

Here, for (1) a = 1, b= 12 and c = 24


Hence the x-intercepts of 
Answer:
i need more info
Step-by-step explanation:
You need two pieces and 1 has to be 2x longer than the other
set x as the smaller piece (easier to always go with the smaller value as x)
the other piece is 2x (double in size)
your equations would be 3x=240>>> x= 60
so smaller piece/ x= 60
bigger piece/ 2x= 120
Given function is

now we need to find the value of k such that function f(x) continuous everywhere.
We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.
So we just need to find both left and right hand limits then set equal to each other to find the value of k
To find the left hand limit (LHD) we plug x=-4 into 3x+k
so LHD= 3(-4)+k
To find the Right hand limit (RHD) we plug x=-4 into

so RHD= 
Now set both equal





k=-0.47
<u>Hence final answer is -0.47.</u>