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Ray Of Light [21]
3 years ago
7

3(5+6) ??? its distributive property

Mathematics
2 answers:
Luden [163]3 years ago
6 0
To answer this we will use the distributive poverty. Lets do it:-

3(5+6)
3 · 5 = 15
3 · 6 = 18
15 + 18 = 33

So, 3(5+6) = 33.

Hope I helped ya!! 
kaheart [24]3 years ago
4 0
Yes, we apply the distributive property to simplify this expression.

3*5 = 15
6*3 = 18

15 + 18 is the final answer.
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Answer is 47.25

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dedylja [7]
Absolute value equations have more than one solution because when the answer is in abs. value, it is positive, so there could be a negative answer and it would still be positive. For example |-5|=5 and |5|=5 as well. 
4+|2x|=-1 would have no solution because you cannot have the equation equal a negative since the 2x is in absolute value. 
8 0
3 years ago
let y =2t+5 be a linear function representing the distance from home for an ant t minutes after starting out from a location nea
Akimi4 [234]

Answer: T=1/2 Y + -5/2

Step-by-step explanation:

y=2t+5

2t+5 +-5= y +-5

2t=y-5 2t/2=y-5/2

t=1/2y+-5/2

= t=1/2y + -5/2

7 0
3 years ago
Read 2 more answers
Maria is draining her hot tub at a rate of 5.5 gallons per minute. Is the amount of water left in the pool a function of the amo
AleksandrR [38]

The amount of water in the pool after t minutes is modeled by the linear function V(t) = V(0) - 5t, hence it is a function of time.

A <em>linear function</em> for the amount of water in the pool, considering that it is <u>drained at a rate of a gallons per minute</u>, is modeled by:

V(t) = V(0) - at

  • In which V(0) is the initial volume.

In this problem, draining her hot tub at a rate of <u>5.5 gallons per minute</u>, hence a = 5.5, and:

V(t) = V(0) = 5.5t

Which is a function of time.

To learn more about linear functions, you can take a look at brainly.com/question/13488309

8 0
2 years ago
What is sin 0 when sec 0 = 5? 0 |(1,0) sin e = 2[?] [] Rationalize the denominator if necessary.​
Komok [63]

Answer:

Sin ~0 =\frac{2\sqrt{5} }{5}

Step-by-step explanation:

sec0=\sqrt{5}

cos~0=\frac{1}{sec0} =\frac{1}{\sqrt{5} }

sin ~0=\sqrt{1-cos^2~0}

=\sqrt{1-1/5}=\sqrt{5-1/5}

Sin~0=\sqrt{4/5} =2/\sqrt{5}*\sqrt{5}/\sqrt{5}

Sin~0=2\sqrt{5}/2=2\sqrt{5}/5

<u>--------------------------------</u>

hope it helps...

have a great day!!!

7 0
3 years ago
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