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2 years ago

Please help me thanks!

Mathematics

1 answer:

Svetlanka [38]2 years ago

5 0

The area of the hexagon with side length 5ft and radius 5ft is 64.95 square feet.

<h3>What is a hexagon?</h3>

A hexagon is a polygon with 6 sides.

Analysis:

Find in the attached file the analysis.

In conclusion, the area of the hexagon is 64.95 square ft.

Learn more about regular hexagon: brainly.com/question/1601601

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Sophie [7]

Answer:

Step-by-step explanation:

I graphed it but you could also use the y intercept to determine which function matches the graph

log(x+1)<u>+3</u>

the +3 at the end of the function makes the y-intercept positive 3

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3 years ago

An airline offers daily flights between Chicago and Denver. The total monthly cost C (in millions of dollars) of these flights c

Ira Lisetskai [31]

Answer:

6250

Step-by-step explanation:

Fill in the given number and solve for x. The answer is 1000x, rounded.

$C=\sqrt{0.2x+1}\\\\1.5=\sqrt{0.2x+1} \quad\text{use given value for C}\\\\2.25=0.2x+1 \quad\text{square both sides}\\\\1.25=0.2x \quad\text{subtract 1}\\\\6.25=x \quad\text{multiply by 5}$

x is in thousands, so 6.25×1000 = 6,250 passengers flew in June.

8 0

3 years ago

Add the two expressions.

Ierofanga [76]

-3.2b + 9
by adding like terms together.

3 0

3 years ago

Read 2 more answers

A parent is buying two types of chocolate truffles for the children. The oldest child likes white chocolate (W), the younger two

valkas [14]

Answer:

Each dark chocolate tuffle was $6.

Step-by-step explanation:

This question can be solved by a system of equations.

Four white chocolate truffles (W) cost the same as three dark chocolate truffles (D).

So $4W = 3D$

The parent bought 3 white chocolate truffles(W) and 6 dark chocolate truffles (D), and spent $49.50.

$3W + 6D = 49.50$

$4W = 3D$

$D = \frac{4W}{3}$

$3W + 6D = 49.50$

$3W + 8W = 49.50$

$11W = 49.5$

$W = 4.5$

$D = \frac{4W}{3} = \frac{4*4.5}{3} = 6$

Each dark chocolate tuffle was $6.

6 0

3 years ago

Read 2 more answers

The service life of a battery used in a cardiac pacemaker is assumed to be normally distributed. A random sample of ten batterie

Fittoniya [83]

Answer:

The confidence interval is $25.16 < \mu < 26.85$

Step-by-step explanation:

From the question we are given a data set

25.5, 26.1, 26.8, 23.2, 24.2, 28.4, 25.0, 27.8, 27.3, and 25.7.

The mean of the this sample data is

$\= x = \frac{\sum x_i}{n}$

where is the sample size with values n = 10

$\= x = \frac{25.5+ 26.1+ 26.8+23.2+ 24.2+ 28.4+ 25.0+ 27.8+ 27.3+ 25.7}{10}$

$\= x = 26$

The standard deviation is evaluated as

$\sigma = \sqrt{\frac{\sum (x-\= x)}{n} }$

substituting values

$= \sqrt{\frac{ ( 25.5-26)^2, (26.1-26)^2, (26.8-26)^2, (23.2-26)^2}{10} }$

$\cdot \ \cdot \ \cdot \sqrt{\frac{ ( 24.2-26)^2, (28.4-26)^2+( 25.0-26)^2+ (27.8-26)^2+( 27.3-26)^2+( 25.7-26)^2}{10} }$

$\sigma = 1.625$

The confidence level is given as 90% hence the level of significance is calculated as

$\alpha = 100 -90$

$\alpha =10$ %

$\alpha = 0.10$

Now the critical values of $\frac{\alpha }{2}$ is obtained from the normal distribution table as

$Z_{\frac{\alpha }{2} } = 1.645$

The reason we are obtaining the critical values of $\frac{\alpha }{2}$ instead of $\alpha$ is because we are considering two tails of the area under the normal curve