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3 years ago

13

Using the fundamental poisson brackets find the values of a and b for which the equations represent a canonical transformation g

enerating function

1 answer:

tangare [24]3 years ago

6 0

34567890=- is the answer

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Find the area of the trapazoid for me please :)

Doss [256]

Answer:

A = 14 m^2

Step-by-step explanation:

The area of a trapezoid is found by

A = 1/2 (b1+b2) *h where b is the length of the bases and h is the height

A = 1/2 (2+5) *4

A = 1/2(7)4

A = 14 m^2

6 0

3 years ago

Help me pleaseee I’m still have more works to dooooo

Umnica [9.8K]

Iam sorry i cant see the qusetion

7 0

3 years ago

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Find the surface area of the solid generated by revolving the region bounded by the graphs of y = x2, y = 0, x = 0, and x = 2 ab

Nikitich [7]

Answer:

See explanation

Step-by-step explanation:

The surface area of the solid generated by revolving the region bounded by the graphs can be calculated using formula

$SA=2\pi \int\limits^a_b f(x)\sqrt{1+f'^2(x)} \, dx$

If $f(x)=x^2,$ then

$f'(x)=2x$

and

$b=0\\ \\a=2$

Therefore,

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+(2x)^2} \, dx=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx$

Apply substitution

$x=\dfrac{1}{2}\tan u\\ \\dx=\dfrac{1}{2}\cdot \dfrac{1}{\cos ^2 u}du$

Then

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx=2\pi \int\limits^{\arctan(4)}_0 \dfrac{1}{4}\tan^2u\sqrt{1+\tan^2u} \, \dfrac{1}{2}\dfrac{1}{\cos^2u}du=\\ \\=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0 \tan^2u\sec^3udu=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0(\sec^3u+\sec^5u)du$

Now

$\int\limits^{\arctan(4)}_0 \sec^3udu=2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17})\\ \\ \int\limits^{\arctan(4)}_0 \sec^5udu=\dfrac{1}{8}(-(2\sqrt{17}+\dfrac{1}{2}\ln(4+\sqrt{17})))+17\sqrt{17}+\dfrac{3}{4}(2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17}))$

Hence,

$SA=\pi \dfrac{-\ln(4+\sqrt{17})+132\sqrt{17}}{32}$

3 0

3 years ago

3x-7>5<br> Find the solution, please show your work. Thank You!1

miskamm [114]

To find x just change the <span>> to a =
</span><span>3x-7=5
add 7
3x=12
then divide by 3
x=4

</span>

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3 years ago

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A compound inequality is graphed and its graph consists of all real numbers. Which of the following could have resulted in this

Feliz [49]

"r < 3 or r > 2" is the one among the following choices given in the question that <span>could have resulted in this solution set. The correct option among all the options that are given in the question is the fourth option or option "d". I hope that this is the answer that has actually come to your desired help.</span>

4 0

3 years ago