Which equation can be used to find marc m n? marc m n 150 = 180 marc m n 150 = 360 marc m n – 150 = 180 marc m n – 150 = 360
1 answer:
The complete question is
"Segment MP is a diameter of circle O. Circle O is shown. Line segment M P is a diameter. Line segment N O is a radius. Angle N O P is 150 degrees.
Which equation can be used to find mArc M N?
mArc M N + 150 = 180, mArc M N + 150 = 360, mArc M N – 150 = 180, mArc M N – 150 = 360"
The Equation m Arc(MN) + 150 = 180 is used to find mArc MN. Thus, the correct option is A.
<h3>What is a system of equations?</h3>A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.
It is Given:
Segment MP is the diameter of circle O. Circle O is shown.
Line segment M P is a diameter.
Line segment N O is a radius.
∠NOP = 150°
We need to Find the Equation for m Arc MN
We already know the Diameter subtends 180° as it is the half of Circle 360°
∠NOP = 150°
∴ m(Arc NP) = 150°
The measure of an arc is the measure of its central angle
Therefore,
m Arc Diameter = 180°
m Arc(MN) + m Arc(NP) = 180
m Arc(MN) + 150 = 180
Therefore, the Equation m Arc(MN) + 150 = 180 is used to find mArc MN.
Thus, the correct option is A.
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Answer:
164m (to 3 s.f.)
Step-by-step explanation:
Please see the attached picture for the full solution.
Alright!
To solve, all we need to do is <em>subtract the area of the inner circle from the arear of the outer circle.</em>
But first, we need to find the area of both
Key equation: πr²
π = 3.14
Inner cirle area = π13²
π13² = 530.66
Outer cirle area = π21²
I got 21 by adding 8 and 13: both added together makes the radius of the larger circle
π21² = 1,385.74
Now let's <em>subtract. </em>
1,385.74 - 530.66 = 855.08
The area of the blue is = 855.08 yards²
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Part 2:
Hexagon with 6cm sides and an apothem of
The answer is C. 93.53