Answer:
1.46 x 10⁶g
Step-by-step explanation:
Given parameters:
Weight of each bowling ball = 7.3 x 10³g
Number of balls in the bowling alley = 2.0 x 10²bowling balls
Unknown
The weight of the balls in the alley = ?
Solution:
To find the weight of the balls in the alley, multiply the mass of each balls with the total number of balls;
Weight of the balls = 7.3 x 10³ x 2.0 x 10²
Weight of the balls = (7.3 x 2.0) x 10³⁺²
Weight of the balls = 14.6 x 10⁵g
Therefore, the weight of the balls = 1.46 x 10⁶g
Answer:
Function A has a rate of change of -5 and Function B has a rate of change of -4.5, so Function B has a greater rate of
Step-by-step explanation:
Function A:
Function B:
Required
Which has a greater rate of change
The rate of change of function A is calculated as thus:
Where:
So, we have:
For function B
The general function is:
Where
m is the rate of change
By comparing to
So, we have that:
Function A has a rate of -5; function B has a rate of -4.5.
By comparison: -4.5 is greater than 5
Hence, function B has a greater rate.
Answer:
y = 1
Step-by-step explanation:
x + y = 16
x - y = 14 add the equations
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2x = 30
x = 15
x + y = 16
15 + y = 16
y = 1
the numbers are 15 and 1
Answer:
- m=y2-y1 / x2-x1
- m= 5-2 / 9-0
- 3/9 =1/3
- y=mx+b
- 2=1/3(0)+b
- 2=b
- slope is 1/3
- y-intr is 2
Step-by-step explanation:
Answer:
Step-by-step explanation:
As with any equation involving fractions, you can multiply the equation by the least common denominator to eliminate fractions. Then solve in the usual way.
c) 1/a +b = c
1 +ab = ac . . . . multiply by a
1 = ac -ab . . . . subtract ab
1 = a(c -b) . . . . . factor out a
1/(c -b) = a . . . . divide by the coefficient of a
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d) (a-b)/(b-a) = 1
a -b = b -a . . . . . multiply by b-a
2a = 2b . . . . . . . . add a+b
a = b . . . . . . . . . . divide by the coefficient of a
Please be aware that this makes the original equation become 0/0 = 1. This is why a=b is not an allowed condition for this equation. As written, it reduces to -1 = 1, which is false. One could say <em>there is no solution</em>.
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f) bc +ac = ab . . . . . multiply by abc
bc = ab -ac . . . . . . subtract ac
bc = a(b -c) . . . . . . factor out a
bc/(b -c) = a . . . . . . divide by the coefficient of a
