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kvv77 [185]
2 years ago
5

Select the correct answer from each drop-down menu. Right triangle ABC is represented with the right angle at vertex B. Base BC

measures 10 inches and angle C measures 40 degrees. In the figure, AB = inches and AC = inches.
Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
6 0

By using trigonometric relations, we will see that:

AC = 15.6 in

AB = 8.4 in.

<h3>How to get the measures of the other two sides of the right triangle?</h3>

Here we have the right triangle where:

B = 90°

C = 40°

BC = 10 in.

Notice that is the adjacent cathetus to the angle C, then we can use the two relations:

  • sin(a) = (adjacent cathetus)/(hypotenuse).
  • tan(a) = (opposite cathetus)/(adjacent cathetus).

Where:

  • hypotenuse = AC
  • opposite cathetus = AB.

Then we will have:

sin(40°) = 10in/AC.

AC = 10in/sin(40°) = 15.6 in

tan(40°) = AB/10in

tan(40°)*10in = AB = 8.4 in.

So we can conclude that for the given right triangle we have:

AC = 15.6 in

AB = 8.4 in.

If you want to learn more about right triangles:

brainly.com/question/2217700

#SPJ1

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Hank spend 76% of his monthly salary and saves $270 find his monthly salary
Dimas [21]

Answer:

f $270= the remaining 24% then you want to do 270/24=11.25 Then you want to multiply that by 76 and you will get $855

So $270+$855=24%+76% So his monthly salary was $1,125

If you are still confused do it in reverse! 1,125/100=11.25

11.25•24=270 & 11.25•76=855

270+855=1,125

Step-by-step explanation:

the guy below copied me

4 0
2 years ago
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Oxana [17]

Answer:

Slope=-1

Step-by-step explanation:

Slope=y1-y2/x1-x2

Where (X1,y1)(0,8) and (X2,y2) (4,4)

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So slope is -1

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3 years ago
What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c
zysi [14]

Answer:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

Step-by-step explanation:

Given

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Required

Simplify

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Cancel out 18

\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}

Divide 4 and 2

\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}

Divide 27 and 12 by 3

\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}

Apply law of indices

\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}

\frac{9a^5 * b^3 * 2c }{4}

Divide 2 and 4

\frac{9a^5 * b^3 * c}{2}

\frac{9a^5b^3c}{2}

Rewrite as:

\frac{9}{2}a^5b^3c

Hence:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

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svet-max [94.6K]

Answer:

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B and D are the only ones with the same slope (-3x) which is required for the line to be parallel.

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