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Rainbow [258]
2 years ago
11

Correct answer get brainliest!! Determine if the following triangles are congruent if yes state what theorem proves them to be

Mathematics
1 answer:
AnnZ [28]2 years ago
3 0

Answer: AAS

Step-by-step explanation:

We know that \angle TSN \cong \angle HSU because they are vertical angles, meaning the triangles are congruent by <u>AAS.</u>

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Need help with #12<br> Please help
Korolek [52]

Step-by-step explanation:

If the figure is triangle then,

Let PR be x

So,

PQ+QR+PR= 180 (Sum of all the angles of the triangle)

Therefore,

6x+25+16-3x+x=180

4x+36=180

4x= 180/36

x= 144/4

X= 36

NOW,

PQ= 6x+25

= 6(36)+25

= 216+25 = 241= PQ.

QR = 16-3x

= 16-3(36)

= 16-108

= -92

PR = 36

hope it helps

5 0
2 years ago
Maria has a bag with 6 red marbles, 6 blue marbles, and 4 green marbles looking Maria picks one . She does not replace it and sh
Sati [7]

Answer: Hello there!

initially Maria has 6 red marbles, 6 blue marbles, and 4 green marbles.

You know that in the first pick, Maria gets a green marble ( this means that now there are 3 green marbles left)

Now we want to know the probability that she gets a red marble on the second pick.

Now there are 6 + 6 + 3 = 15 marbles in the bag, and 6 of them are red ones. Then the probability of getting one red is the number of red ones divided by the total amount ( which is the ratio of red marbles to total marbles)

this is 6/15.

now you can see that there is no 6/15 in the options, so we need to see which one is equivalent.

if we took the option C, 2/5, and multiply both denominator and numerator by 3, we get (3*2)/(3*5) = 6/15, then 2/5 and 6/15 are equivalents.

Then the correct answer is C.

Step-by-step explanation:

5 0
2 years ago
8.Find the value of c that makes the expression be a perfect square trinomial p^2-30p+c
Darina [25.2K]
Hope this is the right one.

Problem 8
p^2 - 30p + c
<em>Step One</em>
Take 1/2 of - 30
1/2 * -30 = - 15

<em>Step 2
</em>Square -15
(-15)^2 = 225
c = 225

Problem Nine
\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a} &#10;
a = 1
b = 4
c = -15
\text{x = }\dfrac{ -4 \pm \sqrt{4^{2} - 4*1*(-15) } }{2*1}
\text{x = }\dfrac{ -4 \pm \sqrt{\text{16} + \text{60} } }{2}

x = [-4 +/- sqrt(76)] / 2
x = [-4 +/- 2*sqrt19]/2
x = [-4/2 +/- 2/2 sqrt[19]
x = - 2 +/- sqrt(19) 

x1 = - 2 + sqrt(19)
x2 = -2 - sqrt(19)

These two can be broken down more by finding the square root. I will leave them the way they are.  It's just a calculator question if you want it to go into decimal form.

Problem Ten

a = 1
b = 4
c = -32

The discriminate is sqrt(b^2 - 4ac)
D = sqrt(b^2 - 4ac)
D = sqrt(4^2 - 4(1)(-32)
D = sqrt(16 - - 128)
D = sqrt(16 + 128)
D = sqrt(144)
D = +/- 12

Since D can equal + or minus 12 there must be 2 possible (and different) roots. As a matter of fact, this quadratic can be factored.
(x + 8)(x - 4) = y 
But that' s not what you were asked for.
The discriminate is >  0 so the roots are going to be real.
<em>Answer; The discriminate is > 0 so there will be 2 real different roots.</em>

4 0
3 years ago
A computer assembling company receives 24% of parts from supplier X, 36% of partsfrom supplier Y, and the remaining 40% of parts
Ivan

Answer:

thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)

Step-by-step explanation:

denoting A= a piece is defective , Bi = a piece is defective from the i-th supplier and Ci= choosing a piece from the the i-th supplier

then

P(A)= ∑ P(Bi)*P(C) with i from 1 to 3

P(A)= ∑ 5/100 * 24/100 + 10/100 * 36/100 + 6/100 * 40/100 = 9/125

from the theorem of Bayes

P(Cz/A)= P(Cz∩A)/P(A)

where

P(Cz/A) = probability of choosing a piece from Z , given that a defective part was obtained

P(Cz∩A)= probability of choosing a piece from Z that is defective = P(Bz) = 6/100

therefore

P(Cz/A)= P(Cz∩A)/P(A) = P(Bz)/P(A)= 6/100/(9/125) = 5/6 (83.33%)

thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)

8 0
3 years ago
Read 2 more answers
HElp me find the IQR please
patriot [66]
The interquartile range is 4
8 0
2 years ago
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