Answer:
55 adult tickets were sold on Friday.
Step-by-step explanation:
A linear system will be used to model the system.
Let c be the number of child tickets and a be the number of adult tickets
Then according to given statements
From equation 1
Putting this in equation 2
Putting c = 78 in equation 1
Hence,
55 adult tickets were sold on Friday.
Answer:
-q^2 -q + 72
Step-by-step explanation:
(9+ q)(8-q)
=9(8-q)+ q(8-q)
=72 - 9q +8q -q^2
= -q^2 -q + 72
March is 8 months away from August and the target amount is $600.
August = $50
September = $50 + (0.2*50)=$60
October = $60 + (0.2*60)=$72
November=$72+(0.2*72)=$86.4
December=$86.4 + (0.2*$86.4)=$103.68
January=$103.68+(0.2*103.68)= $124.416
February=$124.416+(0.2*124.416)=$149.3
March=$149.3 +(0.2*149.4)=$179.2
Total amount = $824.6
Yes, she will have money for the trip
Answer:
10
Step-by-step explanation:
say x=0
then y would be 1
increasing x by 5 makes x=5
and then 5 x 2 + 1=11
so y went from 1-11(difference of 10) with the variation
so the answer is 10
To get a close estimate, we can round 49 up to 50 and 311 down to 300, obtaining an estimate of 50/300 = 1/6, or 0.1666... as a repeating decimal. That decimal approximation is a little less than one hundredth away from the actual decimal approximation of ≈ 0.1576
