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1 year ago

Please reference the photo below

Mathematics

1 answer:

Art [367]1 year ago

5 0

Answer:

1824

Step-by-step explanation:

200 x (1 + 0.325%)^9 - 1 / 0.325%

200 x (1 + 0.00325)^9 - 1 / 0.00325

200 x 1.00325^9 - 1 / 13/4000

200 x (4013 / 4000)^9 - 1 / 13/4000

200 x 4013^9 / 4000^9 - 1 / 13/4000

200 x 4013^9 - 4000^9 / 4000^9 / 13/4000

200 x 4013^9 - 4000^9 / 13 - 4000^8

4013^9 - 4000^9 / 13 x 20 x 4000^8

4013^9 - 4000^9 / 260 x 4000^8

1823.5

1824

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What is 12.25 as a fraction

Finger [1]

Answer:

$\large\boxed{12.25=\dfrac{49}{4}}$

Step-by-step explanation:

$12.\underbrace{25}_{2}=\dfrac{1225}{1\underbrace{00}_2}=\dfrac{1225:25}{100:25}=\dfrac{49}{4}\\\\12.25=12+0.25=12+\dfrac{25}{100}=12+\dfrac{25:25}{100:25}=12+\dfrac{1}{4}\\\\=\dfrac{12\cdot4}{4}+\dfrac{1}{4}=\dfrac{48+1}{4}=\dfrac{49}{4}$

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2 years ago

Which is the value of this expression when p=-2 and q=-1?

saul85 [17]

Answer:

D. 4

Step-by-step explanation:

$[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4$

8 0

2 years ago

Use the quadratic formula to find solutions to the following:

Mumz [18]

Website Math papa can help w that

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2 years ago

Find a_1 and d for an arithmetic sequence with these terms. a_4=9and a_7=18

jonny [76]

$\bf \begin{array}{llll}
term&value\\
-----&-----\\
a_4&9\\
a_5&9+d\\
a_6&(9+d)+d\\
&9+2d\\
a_7&(9+2d)+d\\
&9+3d=\underline{18}
\end{array}\\\\
-------------------------------\\\\
9+3d=18\implies 3d=9\implies d=\cfrac{9}{3}\implies \boxed{d=3}$

$\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=7\\
d=3
\end{cases}
\\\\\\
a_7=a_1+(7-1)d\implies 18=a_1+(7-1)3\implies 18=a_1+18
\\\\\\
18-18=a_1\implies \boxed{0=a_1}$

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3 years ago

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valentina_108 [34]

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3 years ago