Answer:
The larger acute angle is equal to 50.8 degrees.
Step-by-step explanation:
Let's solve for both of the acute angles for the purpose of checking our work at the end with angle A being the top angle and angle B being the one on the base of the triangle (that's not the 90 degrees one). Determining whether to use sin/cos/tan comes from SOH-CAH-TOA.
A = cos^-1 (2√6/2√15)
However, you need to move the radical out of the denominator by multiplying √15 to the numerator and denominator. You should come up with (2√90)/30. So,
A = cos^-1 (2√90/30) = 50.768 degrees.
B = sin^-1 (2√90/30) = 39.231 degrees.
Now, we can check the work by adding the 2 angles to 90 and, if it comes to 180, it's right.
cos^-1 (2√90/30) + sin^-1 (2√90/30) + 90 = 180.
If you have any questions on where I got a formula or any step, feel free to ask in the comments!
You would use the volume of a cone formula ((1/3)(pi)(r^2)h) so it would be (1/3)(pi)(7^2)(24). That simplified to 392(pi) units^3. So the answer is c
I think C is the answer.
In the box, everything is evened out and nothing is bigger than the other.
So, your answer:
C
Answer:
x = 11
Step-by-step explanation:
If the segments are congruent then
3x = x + 22 ➡ 3x - x = 22
2x = 22 divide both sides by 2
x = 11
