Answer:
8428
Step-by-step explanation:
According to the Question,
- Given, A theater has 56 rows of seats. If there are 13 seats in the first row, 18 in the 2nd row, 23 in the 3rd row.
We have a number sequence 13, 18, 23, ...
- We can say that this is an arithmetic sequence because of the common difference 'd', is equal to 5, and the first term 'a1' is equal to 13.
- The formula for the sum of an arithmetic sequence with n terms is given is
![S_n= \frac{n}{2} [2a_1+(n-1)d]S](https://tex.z-dn.net/?f=S_n%3D%20%5Cfrac%7Bn%7D%7B2%7D%20%5B2a_1%2B%28n-1%29d%5DS)
.
Substitute the given values into the equation to solve for the sum of the 56 rows of seats.
![S_56= \frac{56}{2}[2(13)+(56-1)(5)]\\S_{56}=28\left[26+275\right]\\S_{56}=28\left[301\right]\\S_{56}=8428](https://tex.z-dn.net/?f=S_56%3D%20%5Cfrac%7B56%7D%7B2%7D%5B2%2813%29%2B%2856-1%29%285%29%5D%5C%5CS_%7B56%7D%3D28%5Cleft%5B26%2B275%5Cright%5D%5C%5CS_%7B56%7D%3D28%5Cleft%5B301%5Cright%5D%5C%5CS_%7B56%7D%3D8428)
Therefore, there are 8428 seats in all.
The numbers are: "7 " and "21 " .
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Explanation:
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The numbers are: "x" and "x + 14" .
x + (x + 14) = 28 . Solve for "x" ; and then solve for "x + 14" .
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→ x + (x + 14) = 28 ;
Rewrite as:
→ x + x + 14 = 28 ;
→ 1x + 1x + 14 = 28 ;
→ 2x + 14 = 28 ;
Subtract "14" from each side of the equation;
→ 2x + 14 − 14 = 28 <span>− 14 ;
</span> → 2x = 14 ;
Divide EACH SIDE of the equation by "2" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ 2x / 2 = 14 / 2 ;
→ x = 7 .
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So; one of the numbers is: " 7 " .
The other number is: " x + 14 " ; which equals: " 7 + 14 = 21".
The other number is: "21 " .
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The numbers are: "7 " and "21 " .
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The answer is y=22 I think
Greater than 1.Because 1.25-0.25=1.23.That's it.
