Question

Compute the following 8c8 a. 16 b. 0 c. 64 d. 1

Answer 1

Answer:

d. 1

Step-by-step explanation:

To solve for the combination, you just need to remember the formula:

$_{n}C_{r}=\dfrac{n!}{r!(n-r)!}$

So you just need to fill in the formula:

$_{n}C_{r}=\dfrac{n!}{r!(n-r)!}$

$_{8}C_{8}=\dfrac{8!}{8!(8-8)!}$

$_{8}C_{8}=\dfrac{8!}{8!(0)!}$

$_{8}C_{8}=\dfrac{8!}{8!}$

$_{8}C_{8}=1$