All categories

3 years ago

Y=−6x+3 rewrite in standard form

Mathematics

2 answers:

KIM [24]3 years ago

7 0

Answer:

6x+y=3

Step by step:

Standard Form: Ax+By=C

Move Ax and By onto the same sides. y=-6x+3

-6x turns into a positive 6x because you are adding 6x onto both sides of the equation.

Aloiza [94]3 years ago

5 0

Answer:

6x + y = 3

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Given

y = - 6x + 3 ( add 6x to both sides )

6x + y = 3 ← in standard form

You might be interested in

Help me pls this is urgent ;>

postnew [5]

Answer:

$\frac{ |a + x| }{2} - \frac{ |a - x| }{2} \\ \\ = \frac{ | - 2 - 6| }{2} - \frac{ | - 2 + 6| }{2} \\ \\ = \frac{ | - 8| }{2} - \frac{ |4| }{2} \\ \\ = \frac{8}{2} - \frac{4}{2} \\ \\ = 4 - 2 = 2$

5 0

3 years ago

Solve for n: 21 K - 3n + 9 p is greater than 3 p + 12

Digiron [165]

Answer:

n > p + 1 + 7k

Step-by-step explanation:

21k - 3n + 9 > 3p + 12

21k - 3n > 3p + 12 - 9

3n > 3p + 3

3n > 3p + 3 + 21k

n > (3p + 3 + 21k)/3

n > p + 1 + 7k

6 0

3 years ago

23 096 145

Yuri [45]

Answer:

twenty three million ninety six thousand one hundered fourty five

Step-by-step explanation:

not needed

4 0

2 years ago

HELP ASAP Linear Equations

Scilla [17]

Answer:

4th choice: I and IV only

Step-by-step explanation:

Change the form of the given equation to standard form.

y = -2/3 x + 2

3y = -2x + 6

2x + 3y = 6

Now compare this equation with the 4 choices.

Any equation that has the same x- and y-terms but a different constant term is parallel.

I. is parallel.

II. and III. are not parallel.

Look at IV.:

4x + 6y = 3

Divide both sides by 2:

2x + 3y = 3/2

IV. is also parallel.

Answer: 4th choice: I and IV only

4 0

3 years ago

Read 2 more answers

Two brothers want to share a large field equally.

Elan Coil [88]

Yes, the partition gives the two brothers equal shares.

Step-by-step explanation:

Step 1:

Assume the entire field has an area of B. So one brother takes $\frac{1}{12} B$ , $\frac{1}{6}B$ , and $\frac{1}{4} B$

So we need to calculate how much this brother takes in terms of B.

To do this we calculate how much $\frac{1}{12} B + \frac{1}{6} B + \frac{1}{4} B$ is.

Step 2:

To add $\frac{1}{12} B + \frac{1}{6} B + \frac{1}{4} B$ ,

First take the LCM of the denominators 12, 6, and 4

The LCM is 12, we multiply the denominator to get the LCM value, this same value is multiplied to the numerator too.

$\frac{1}{12} B + \frac{1}{6} B + \frac{1}{4} B = \frac{1(1)}{12(1)} B + \frac{1(2)}{6(2)} B + \frac{1(3)}{4(3)} B \\\\\frac{1}{12} B + \frac{1}{6} B + \frac{1}{4} B= \frac{1B +2B+3B}{12} = \frac{B}{2}$

Step 3:

One brother gets $\frac{1}{2} B$ , so we need to calculate how much the other brother gets.

The other brother's share = $B - \frac{1}{2} B = \frac{1}{2}B$

So both the brothers get equal shares

7 0

4 years ago