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Romashka-Z-Leto [24]
2 years ago
10

Hii! I need some help, would anyone mind helping me?

Mathematics
1 answer:
Kisachek [45]2 years ago
8 0

Step-by-step explanation:

{x}^{2}  - 14x  - 25 {y}^{2}  + 100y = 76

Factor by grouping,

( {x}^{2}  - 14x)   - (25 {y}^{2}  - 100y) = 76

Complete the square, with the x variables,

( {x}^{2}  - 14x + 49)  - (25 {y}^{2}  - 100y) = 125

Factor out 25 for the y variables

( {x}^{2}  - 14x + 49) - 25( {y}^{2}  - 4y) = 125

Complete the square

( {x}^{2}  - 14x + 49) - 25( {y}^{2}  - 4y + 4) = 25

Simplify the perfect square trinomial

(x - 7) {}^{2}  - 25(y - 2) {}^{2}  = 25

Make the right side be 1 so divide everything by 25.

\frac{(x - 7) {}^{2} }{25}  -  (y - 2) {}^{2}  = 1

Here our center is (7,2).

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Read 2 more answers
Carlos drew a plan for his garden on a coordinate plane. Rose bushes are located at A(–5, 4), B(3, 4), and C(3, –5)
BartSMP [9]

Given:

A(-5,4)

B(3,4)

C(3,-5)

So point D is:

so point D is (-5,-5)

For AB is

Distance between two point is:

\begin{gathered} (x_1,y_1)and(x_2,y_2) \\ D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \end{gathered}

so distance between A(-5,4) and B(3,4) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(4-4)^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

So AB is 8 unit apart.

For B(3,4) and C(3,-5).

\begin{gathered} D=\sqrt[]{(3-3)^2+(-5-4)^2} \\ =\sqrt[]{0^2+(-9)^2} \\ =9 \end{gathered}

So BC is 9 unit apart.

For fourth bush point is (-5,-5) it left of point C(3,-5) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(-5-(-5))^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

so fourth bush is 8 unit left of C.

For fourth bush(-5,-5) below to point A(-5,4)

\begin{gathered} D=\sqrt[]{(-5-(-5))^2+(4-(-5))^2} \\ =\sqrt[]{0^2+9^2} \\ =9 \end{gathered}

so fourth bush 9 units below of A.

8 0
1 year ago
PLEASE HELP ASAP!! ONLY IF YOU KNOW THE ANSWER! THANK YOU SO MUCH!
telo118 [61]

Answer:

f(x)=-x

I hope this helps :)

8 0
3 years ago
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