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denpristay [2]
3 years ago
12

Is the perimeter of the composite figure equal to the sum of the perimeters of the individual figures? Explain by selecting all

the statements that apply.
yes; To find the perimeter of the composite figure, add the perimeters of each of the individual figures.
yes; To find the perimeter of the composite figure, multiply the perimeters of the individual figures.
no; To find the perimeter of a composite figure, find the distance around the figure.
no; The perimeter of the composite figure does not include the measure of the shared side.
Which ones do I pick?
Mathematics
2 answers:
DIA [1.3K]3 years ago
6 0

Answer: No the third one , you have to find the distance around the figure

Step-by-step explanation:

blagie [28]3 years ago
6 0

Answer:

is the third one bro I had the same hw in perimeter on the composite figure

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A corporate team building event costs $2 for every attendee. If there are 8 attendees how much will the corporate team building
lesantik [10]

Answer:

16$

Step-by-step explanation:

8 times 2 is 16

I hope this helps!!!

7 0
3 years ago
A store pays $399 for a waterheater. The store marks up the price by 42% . What is the amount of the mark-up?
Lelu [443]

Answer:

Step-by-step explanation:

399*42%= 167.58 the mark up amount

399+167.50=566.50 total

3 0
3 years ago
Please help with question below.
Nonamiya [84]

Answer:

Step-by-step explanation:

We have to find the points that are on the graph by finding the order pair (x, y) We are given the x value, so substitute x in the given equation f(x) and find y.

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6 0
3 years ago
If varies inversely as . It is known that = 10 when = 3, find the value of when = 5.
Leto [7]

Answer:

y = 6

Step-by-step explanation:

If x varies inversely proportional as y.

x=\dfrac{k}{y}, k is constant of proportionality

or

k = xy

When x = 3 and y = 10

k = 3×10

k = 30

Put x = 5,

y=\dfrac{k}{x}\\\\y=\dfrac{30}{5}\\\\y=6

So, the value of y is 6 when x is 5.

8 0
2 years ago
Linear Programming:
tatuchka [14]
Let the number of large bookcases be x and number of small bookcases be y, then
Maximise P = 80x + 50y;
subkect to:
6x + 2y ≤ 24
x, y ≥ 2

The corner points are (2, 2), (2, 6), (3.333, 2)
For (2, 2): P = 80(2) + 50(2) = 160 + 100 = 260
For (2, 6): P = 80(2) + 50(6) = 160 + 300 = 460
For (3.333, 2): P = 80(3.333) + 50(2) = 266.67 + 100 = 366.67

Therefore, for maximum profit, he should produce 2 large bookcases and 6 small bookcases.
7 0
3 years ago
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