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Alinara [238K]
2 years ago
14

What is the mean of the data set? 8, 16, 9, 11 A 9 B 10 C 12 D 11

Mathematics
1 answer:
devlian [24]2 years ago
6 0
You add all the numbers and then divide by how many numbers there were to find the mean or average. In this case it is D 11
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Jeff must do a book report. He reads 3 pages of his book in 13 minutes. He reads 9 pages of his book in 39 minutes. He reads 15
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7 0
4 years ago
This is all the points i have left please help please with either
nekit [7.7K]

Answer:

For question 26 the answer is ( 9^210 )

For question 27 the answer is ( 24 )

Step-by-step explanation:

<em><u>For question number 26</u></em><em><u>:</u></em> try on the scientific calculator the equation you have pictured it will give you a very long number beginning with 《 2459953978》

Then put the the 9^210 on the calculator and click ( =) if it didn't work try clicking S》D then you will get the same long number Count at least the first 6 numbers for assurance

<em><u>For question number 27 </u></em><em><u>:</u></em><em><u>The volume of a right cone is given by </u></em>

<em><u>v =   \frac{1}{3} \pi \ \: {r}^{2} h</u></em>

<em><u> Here, you only know the value of one of the variables, V, so you'll need to use the information in the question to somehow write r and h in terms</u></em>

<em><u>If the cone is three times as wide at the base as it is tall, then call the diameter 3x and the height of the cone one-third of that, or x. The volume formula calls for the radius, which is half the diameter, or </u></em>

<em><u>\frac{3x}{2}</u></em>

<em><u>Substitute these values into the formula and solve for x:</u></em>

<em><u>384\pi =  \frac{1}{3} \pi {( \frac{3}{2}\pi) }^{2} x \\ 384 = ( \frac{1}{3} )( \frac{9}{4}  {x}^{2} )x \\ 384 =  \frac{3}{4}  {x}^{3 }  \\ 512 =  {x}^{3 }  \\  \sqrt[3]{512}  = x \\ 8 = x \\</u></em>

The question asks for the diameter of the base, which is 3x = 3(8) = 24.

8 0
3 years ago
What in the times tables equal 48?
babymother [125]
2,3.4,6,7,8. I think that's it from 2-10.
8 0
3 years ago
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