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Ksju [112]
3 years ago
6

If a couple plans to have 7 ​children, what is the probability that there will be at least one girl​? Assume boys and girls are

equally likely. Is that probability high enough for the couple to be very confident that they will get at least one girl in 7 ​children?
Mathematics
1 answer:
Kisachek [45]3 years ago
6 0
<h2>Answer with explanation:</h2>

Given : The number of children a family plans to have = 7

If the boys and girls are equally likely, then the probability of getting a girl = probability of getting boy = \dfrac{1}{2}=0.5

Now, the probability  that there will be at least one girl​ will be:-

P(atleast one girl) = 1- P(all boys)

=1-(\dfrac{1}{2})^7\\\\=1-0.0078125\\\\=0.9921875

Hence, the probability that there will be at least one girl​ = 0.9921875

Since ,0.9921875 > 0.5  

It means the event is likely to happen.   [∵Any event E is likely to happen if P(E)>0.5]

Therefore, the probability is high enough for the couple to be very confident that they will get at least one girl in 7 ​children.

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Round 18.159 to the nearest tenth
Mandarinka [93]

Answer:

18.2

Step-by-step explanation:

A tenth is the first decimal, on the right of your unit. 5 to the sky (round up) 4 to the floor (round down)

5 0
2 years ago
Consider a right triangle that has these dimensions: the side opposite angle a is 6 meters and the side adjacent angle a is 8 me
Varvara68 [4.7K]
To determine the length of the hypotenuse, we need a relation that would relate the other legs and the hypotenuse of the triangle. So, we would need to use the Pythagorean theorem which is an equation that relates the hypotenuse with the other legs of a right triangle. It is to be noted that this is only usable for right triangles only. It is expressed as follows:

c^2 = a^2 + b^2

where c is the hypotenuse and a, b are the other legs.

c = √(a^2 + b^2)
c = √(6^2 + 8^2)
c = √100
c = 10 m

Therefore, the length of the hypotenuse with the other legs having a length of 6 and 8 would be 10 m.
5 0
3 years ago
I need some help with math
Irina18 [472]

Answer:

(y-7)^2+(x-2)^2=16

and

(x+2)^2+(y-15)^2 = 9

Step-by-step explanation:

The standard equation of a circle is (x-h)^2+(y-k)^2=r^2 where the coordinate (h,k) is the center of the circle.  

Second Problem:

  1. We can start with the second problem which uses this info very easily.
  2. (h,k) in this problem is (-2,15) simply plug these into the equation. (x--2)^2+(y-15)^2=r^2 .
  3. We can also add the radius 3 and square it so it becomes 9. The equation.
  4. This simplifies to (x+2)^2+(y-15)^2 = 9.

First Problem:

  1. The first problem takes a different approach it is not in standard form. But we can convert it to standard form by completing the square.
  2. y^2-14y+x^2-4x+37=0 first subtract 37 from both sides so the equation is now y^2-14y+x^2-4x=-37.
  3. y^2-14y+x^2-4x+37=0 by adding (-\frac{b}{2a} )^2 to both the x and y portions of this equation you can complete the squares. (-\frac{b}{2a})^2=(-\frac{-14}{2(1)})^2 and (-\frac{-4}{2(1)})^2 which equals 49 and 4.
  4. Add 49 and 4 to both sides and the equation is now:y^2-14y+49+x^2-4x+4=-37+49+4 You can simplify the y and x portions of the equations into the perfect squares or factored form (y-7)^2 and (x-2)^2.
  5. Finally put the whole thing together. (y-7)^2+(x-2)^2=16.

I hope this helps!

5 0
3 years ago
More math questions if you would
Sholpan [36]

Answer:

A.

Step-by-step explanation:

So we are given the function:

f(x)=7x+8

To find the inverse of the function, we simply need to flip <em>f(x)</em> and <em>x</em> and then solve for <em>f(x)</em>. Thus:

x=7f^{-1}(x)+8\\x-8=7f^{-1}(x)\\f^{-1}(x)=\frac{x-8}{7}

So the answer is A.

7 0
3 years ago
Read 2 more answers
Please answer number 2
viva [34]
They aren't necessarily equal because, for example, 3/2 = 1 remainder 1 and 5/4 = 1 remainder 1 aren't equal because it takes 2 x 1 = 2 + 1 = 3 while 4 x 1 = 4 + 1 = 5. They are the same quotient and remainer, except they aren't used to check if it multiplys back to the same divended.
8 0
3 years ago
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