If a couple plans to have 7 children, what is the probability that there will be at least one girl? Assume boys and girls are
1 answer:
<h2>Answer with explanation:</h2>
Given : The number of children a family plans to have = 7
If the boys and girls are equally likely, then the probability of getting a girl = probability of getting boy =
Now, the probability that there will be at least one girl will be:-
P(atleast one girl) = 1- P(all boys)
Hence, the probability that there will be at least one girl = 0.9921875
Since ,0.9921875 > 0.5
It means the event is likely to happen. [∵Any event E is likely to happen if P(E)>0.5]
Therefore, the probability is high enough for the couple to be very confident that they will get at least one girl in 7 children.
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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Answer:
The minimum score of those who received C's is 67.39.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
If 69.5 percent of the students received grades of C or better, what is the minimum score of those who received C's?
This is X when Z has a pvalue of 1-0.695 = 0.305. So it is X when Z = -0.51.
The minimum score of those who received C's is 67.39.