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gtnhenbr [62]
2 years ago
6

="absmiddle" class="latex-formula">
Mathematics
2 answers:
Minchanka [31]2 years ago
8 0

Answer:

07698+96965#5_(-&)!:86539'6";

Zigmanuir [339]2 years ago
5 0

The solution to the given expression will be \dfrac{-8\pm\sqrt{180}}{6}.

<h3>What is a quadratic equation?</h3>

The polynomial having a degree of two or the maximum power of the variable in a polynomial will be 2 is defined as the quadratic equation and it will cut two intercepts on the graph at the x-axis.

The given equation will be solved as:-

= 3x² + 8x - 10  

Using the formula of factors:-

x = \dfrac{-b\pm\sqrt{b^-4ac}}{2a}

x = \dfrac{-8\pm\sqrt{64-(-120)}}{2\times 3}

x = \dfrac{-8\pm\sqrt{180}}{6}.

Therefore the solution to the given expression will be \dfrac{-8\pm\sqrt{180}}{6}.

To know more about quadratic equations follow

brainly.com/question/1214333

#SPJ1

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An angle, theta, is in standard position and its terminal side passes through the point (2,-1). Find the EXACT value of sin thet
Olenka [21]

Answer:

sinѲ = -1/√5 or -√5/5

Step-by-step explanation:

On the Cartesian plane, we have radius (r) and angle (Ѳ) theta.

On the Cartesian plane we also have x, y where:

x = r cosѲ .......Equation 1

and y = r sinѲ ........Equation 2

r = √x² + y²

In the question we are given points (2,-1)

Where x = 2 , y = -1

We would solve for r by substituting 2 for x and -1 for y

r = √ 2² + -1²

r = √ 4 + 1

r = √5

In the question, we were asked to find what sin theta (Ѳ) is. Hence, we would be substituting √5 for r in Equation 2

y = r sinѲ

Where y = -1 and r = √5

-1 = √5 sinѲ

Divide both sides by √5

sinѲ = -1/√5

We can also represent sin Ѳ in a proper form, by multiplying both top and bottom by √5

sinѲ = -√5/5

Therefore, sinѲ = -1/√5 of -√5/5

6 0
4 years ago
Rewrite these in increasing order of length:<br> 133 dm. 433 cm, 308 km, 91 mm
Oksi-84 [34.3K]

\boxed{91mm

<h2>Explanation:</h2>

First of all, let's transform each measurement into meter knowing the following relationships:

1dm=0.1m \\ \\ 1cm=0.01m \\ \\ 1km=1000 m \\ \\ 1mm=0.001m

Therefore, we can compute the following:

\bullet \ 133dm \rightarrow 133dm(\frac{0.1m}{1dm})=13.3m \\ \\ \bullet \ 433cm \rightarrow 433cm(\frac{0.01m}{1cm})=4.33m \\ \\ \bullet \ 308km \rightarrow 308km(\frac{1000m}{1km})=308,000m \\ \\ \bullet \ 91mm \rightarrow 91mm(\frac{0.001m}{1mm})=0.091m

Writing this in increasing order:

0.091m

<h2>Learn more:</h2>

jovian planets in order of increasing distance from the Sun: brainly.com/question/12534549

#LearnWithBrainly

7 0
3 years ago
Hans spent three days baking 224 cookies. On the second day, he baked twice as many as he did on the first day. On the third day
Likurg_2 [28]
He baked 448 cookies on the second day
7 0
3 years ago
Solve the following system.
Harlamova29_29 [7]

Answer:

y=-2,\:\\x=1,\:\\z=-3

Step-by-step explanation:

\begin{bmatrix}y+4z=-14\\ x+3z=-8\\ 2x-3y=8\end{bmatrix}\\\\Isolate\:y\:for\:y+4z =-14\: : \:y=-14-4z\\\\\mathrm{Subsititute\:}y=-14-4z\\\\\begin{bmatrix}x+3z=-8\\ 2x-3\left(-14-4z\right)=8\end{bmatrix}\\\\Isolate\:x\:for\:x+3z =-8\: :\:x =-8-3z\\\mathrm{Subsititute\:}x=-8-3z\\\\\begin{bmatrix}2\left(-8-3z\right)-3\left(-14-4z\right)=8\end{bmatrix}\\\\Simplify\\\\\begin{bmatrix}6z+26=8\end{bmatrix}\\\\Isolate\:z\:for 6z+26=8 \: ;\:z =-3\\\\\mathrm{For\:}x=-8-3z\\\\

\mathrm{Subsititute\:}z=-3\\\\x=-8-3\left(-3\right)\\\\-8-3\left(-3\right)=1\\\\x=1\\\\\mathrm{For\:}y=-14-4z\\\\\mathrm{Subsititute\:}x=1,\:z=-3\\\\y=-14-4\left(-3\right)\\\\-14-4\left(-3\right)=-2\\\\y=-2\\\\\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}\\\\y=-2,\:x=1,\:z=-3

6 0
3 years ago
use the formula S=(2)1/2bh+hw+sw+bw,with the following dimensions,base =3ft,height=2ft,width=5ft,side=4ft what is the surface ar
blondinia [14]
I wish i could help but i dont know it
5 0
3 years ago
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