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Natali [406]
3 years ago
13

Select the quadrant or axis where each ordered pair is located on the a coordinate plane

Mathematics
1 answer:
Ivan3 years ago
3 0

Step-by-step explanation:

Quadrant 1 is when the x axis and y axis is both positive.

Quadrant 2 is when the x axis is negative and the y value is positive.

Quadrant 3 is when the x axis and y axis is negative.

Quadrant 4 is when the x axis is positive and y value is negative.

When the point is on the x axis that means it y intercept is 0.

When the point on the y axis, it x intercept is 0.

2,4 is in quadrant 1

0,-3 is y axis

-1,1/2 is in the second quardrant

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Para embalar una caja se emplea 4,2 m de cinta adhesiva. ?Cuántas cajas se podrán embalar con tres rollos que tienen 3 hm, 7 dam
kompoz [17]

For this case, we perform the conversions:

First roll:

1 \ Hectometer --------> 100 \ meters\\3 \ Hectometer --------> x

x = \frac {3 * 100} {1}\\x = 300 \ meters.

We make a rule of three to determine the number of "c" boxes that can be packed with 300 meters of adhesive tape.

1 -----------> 4.2

c -----------> 300

c = \frac {300 * 1} {4.2}\\c = 71.42857143\\c = 71

You can pack 71 boxes.

Second roll:

1 \ Decametro --------> 10 \ meters\\7 \ Decameter --------> x\\x = \frac {7 * 10} {1}\\x = 70 \ meters.

We make a rule of three to determine the number of "c" boxes that can be packed with 70 meters of adhesive tape.

1 -----------> 4.2

c -----------> 70

c = \frac {70 * 1} {4.2}\\c = 16.66666667\\c = 16

You can pack 16 boxes.

Third roll:

1 -----------> 4.2

c -----------> 50

c = \frac {50 * 1} {4.2}\\c = 11.9047619\\c = 11

You can pack 11 boxes.

Thus, in total you can pack11 + 16 + 71 = 98 \ boxes

Answer:

98 boxes

4 0
3 years ago
What is the answer to this problem?
Pani-rosa [81]
15 CAN I GET A BRAILYIST ANSWER PLEASE

3 0
3 years ago
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The John Jay Theater Dept has tickets at $6 for adults, $4 for teachers, and $2 for students. A total of 280 tickets were sold f
OleMash [197]

Answer:

number of adults tickets sold = x = 90

number of teachers tickets = y = 45

number of students tickets = z = 145

Step-by-step explanation:

Cost of tickets

Adults = $6

Teachers = $4

Students = $2

Total tickets sold = 280

Total revenue = $1010

Let

x = number of adults tickets

y = number of teachers tickets

z = number of students tickets

x + y + z = 280

6x + 4y + 2z = 1010

If the number of adult tickets sold was twice the number of teacher tickets

x = 2y

Substitute x=2y into the equations

x + y + z = 280

6x + 4y + 2z = 1010

2y + y + z = 280

6(2y) + 4y + 2z = 1010

3y + z = 280

12y + 4y + 2z = 1010

3y + z = 280 (1)

16y + 2z = 1010 (2)

Multiply (1) by 2

6y + 2z = 560 (3)

16y + 2z = 1010

Subtract (3) from (2)

16y - 6y = 1010 - 560

10y = 450

Divide both sides by 10

y = 450/10

= 45

y = 45

Substitute y=45 into (1)

3y + z = 280

3(45) + z = 280

135 + z = 280

z = 280 - 135

= 145

z = 145

Substitute the values of y and z into

x + y + z = 280

x + 45 + 145 = 280

x + 190 = 280

x = 280 - 190

= 90

x = 90

Therefore,

number of adults tickets sold = x = 90

number of teachers tickets = y = 45

number of students tickets = z = 145

5 0
3 years ago
A pair of desiner sneakers was bought for $120. Since they were bought their price had increased by 15%. What is the new price
kodGreya [7K]
The base price is $120. 15% in decimal form is 0.15, to get 15% of 120 you multiply the decimal form of 15% by 120.
0.15 * 120 = 18
Since the price increased by 15 percent, and $18 is 15% of 120, we add 18 to 120, so the answer is

$138
8 0
3 years ago
Help please and thank u​
LUCKY_DIMON [66]

Answer:

The line is y = (1/2)x + 3

Step-by-step explanation:

We can calculate a slope.  I'll use the two points (-4,1) and (-1,2.5).

Rise = (2.5-1) = 1.5

Run = (-1-(-4)) = 3

Rise/Run = Slope = (1.5/3.0) = 1/2

Find b, the y-intercept, by using point (-4,1) in the equation y = (1/2)x + b

y = (1/2)x + b

1 = (1/2)*(-4) + b

1 = -2 + b

b=3

The line is y = (1/2)x + 3

8 0
2 years ago
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