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3 years ago

Select the quadrant or axis where each ordered pair is located on the a coordinate plane

Mathematics

1 answer:

Ivan3 years ago

3 0

Step-by-step explanation:

Quadrant 1 is when the x axis and y axis is both positive.

Quadrant 2 is when the x axis is negative and the y value is positive.

Quadrant 3 is when the x axis and y axis is negative.

Quadrant 4 is when the x axis is positive and y value is negative.

When the point is on the x axis that means it y intercept is 0.

When the point on the y axis, it x intercept is 0.

2,4 is in quadrant 1

0,-3 is y axis

-1,1/2 is in the second quardrant

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Please help me determine the equation of the line in slope intercept form and show all work. A line that is perpendicular to the

Airida [17]

Answer:

y=-2x+160

Step by Step:

The equation of a line can be determined using the point slope formula:

y-y1=m (x-x1)

To make a substitution, we must ensure we have the correct information. The question gives:

y1=60

x1=50

y=1/2x+10 This is the formula of a line that is perpendicular to the one we are trying to find.

It tells us that the gradient of the perpendicular line is 1/2. The gradient of the line we are trying to find can be found using m1×m2=-1 because we know that when lines are perpendicular, the product of their gradients must equal 1

So if we replace m1 with 1/2

1/2×m2=-1

m2=-2

We now have all the relevant information to make a substitution:

y-60=-2 (x-50)

expand brackets

y-60=-2x+100

rearrange to get in the form y=mx+b

y=-2x+160

5 0

4 years ago

The probability that your call to a service line is answered in less than 30 seconds is 0.75. Assume that your calls are indepen

vfiekz [6]

Answer:

a) 0.2581

b) 0.4148

c) 17

Step-by-step explanation:

For each call, there are only two possible outcomes. Either they are answered in less than 30 seconds. Or they are not. The probabilities for each call are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$p = 0.75$

a. If you call 12 times, what is the probability that exactly 9 of your calls are answered within 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X = 9)$ when $n = 12$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{12,9}.(0.75)^{9}.(0.25)^{3} = 0.2581$

b. If you call 20 times, what is the probability that at least 16 calls are answered in less than 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X \geq 16)$ when $n = 20$

$P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 16) = C_{20,16}.(0.75)^{16}.(0.25)^{4} = 0.1897$

$P(X = 17) = C_{20,17}.(0.75)^{17}.(0.25)^{3} = 0.1339$

$P(X = 18) = C_{20,18}.(0.75)^{18}.(0.25)^{2} = 0.0669$

$P(X = 19) = C_{20,19}.(0.75)^{19}.(0.25)^{1} = 0.0211$

$P(X = 20) = C_{20,20}.(0.75)^{20}.(0.25)^{0} = 0.0032$

$P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.1897 + 0.1339 + 0.0669 + 0.0211 + 0.0032 = 0.4148$

c. If you call 22 times, what is the mean number of calls that are answered in less than 30 seconds? Round your answer to the nearest integer.

The expected value of the binomial distribution is:

$E(X) = np$

In this question, we have $n = 22$

$E(X) = 22*0.75 = 16.5$

The closest integer to 16.5 is 17.

7 0

3 years ago

Round the number 507,899 to the nearest 10,000

Hitman42 [59]

It's 510,000. Just go to the 10,000 place and round there, then just replace the rest of the numbers with 0's. Don't use a decimal; that would suggest that the number isn't rounded.

4 0

4 years ago

Read 2 more answers

Choose the solution set represented by the following graph.

olga55 [171]

Answer:

The solution set represented by the following graph is:

{x | x∈ R, x < -2}

Step-by-step explanation:

Clearly from the figure we could see that the solution set is to the left of ' -2' and excluding the point '-2' since there is a open circle at -2.

This means that -2 is not included in the set.

Also in interval; form the set of points that belong to the solution set are: