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Natali [406]
3 years ago
13

Select the quadrant or axis where each ordered pair is located on the a coordinate plane

Mathematics
1 answer:
Ivan3 years ago
3 0

Step-by-step explanation:

Quadrant 1 is when the x axis and y axis is both positive.

Quadrant 2 is when the x axis is negative and the y value is positive.

Quadrant 3 is when the x axis and y axis is negative.

Quadrant 4 is when the x axis is positive and y value is negative.

When the point is on the x axis that means it y intercept is 0.

When the point on the y axis, it x intercept is 0.

2,4 is in quadrant 1

0,-3 is y axis

-1,1/2 is in the second quardrant

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Express the illuminance on the floor as a composite function of t for 0 < t < 8.
GrogVix [38]
The formula for illuminance is given by
E = I / d^2
This formula only holds true for one-dimensional illuminance
The problem asks for the illuminance across the floor. We need to use two variables, x and y.
From Pythagorean Theorem
d^2 = x^2 + y^2
and from Trigonometry
x = d cos t
y = d sin t

The function for the illuminance can be represented by the composite function
E = I cos² t / x²
and
E = I sin² t / y²

The boundary of these functions is:
<span>0 < t < 8
So, the value of t must be in radians and not in degrees</span>
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3 years ago
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Please answerrrr Graph g(x), where f(x) = 4x − 2 and g(x) = f(x + 1). a line labeled g of x that passes through points 0, negati
Mrrafil [7]

Answer:

a line labeled g of x that passes through points negative 1, negative 2 and 0, 2

Step-by-step explanation:

we have

f(x)=4x-2

g(x)=f(x+1)

To determine g(x), substitute the variable x by (x+1) in the function f(x)

so

f(x+1)=4(x+1)-2

f(x+1)=4x+4-2

f(x+1)=4x+2

g(x)=f(x+1)

g(x)=4x+2

therefore

a line labeled g of x that passes through points negative 1, negative 2 and 0, 2

4 0
3 years ago
Read 2 more answers
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