Answer:
y=-8/5x+77/5
Step-by-step explanation:
The equation of line that passes through the points (4, 9) and (9, 1) is y=-8/5x+77/5. Hope it helps!
Answer:
10.50°C
Step-by-step explanation:
Given x = 2 + t , y = 1 + 1/2t where x and y are measured in centimeters. Also, the temperature function satisfies Tx(2, 2) = 9 and Ty(2, 2) = 3
The rate of change in temperature of the bug path can be expressed using the composite formula:
dT/dt = Tx(dx/dt) + Ty(dy/dt)
If x = 2+t; dx/dt = 1
If y = 1+12t; dy/dt = 1/2
Substituting the parameters gotten into dT/dt we will have;
dT/dt = 9(1)+3(1/2)
dT/dt = 9+1.5
dT/dt = 10.50°C/s
Hence the rate at which the temperature is rising along the bug's path is 10.50°C/s
Answer:
82
Step-by-step explanation:
f(x) = 5x - 3
g(x) = 2x + 9
f(g(x)) = 5 (2x + 9) - 3 ..... replace x with g(x)
f(g(4)) = 5 * (2 * 4 + 9) -3 = 85 - 3 = 82
Answer:
Make sure the mode is on degree and not radian! Common mistake
