$\begin{bmatrix}-8x+y=-32\\ -3x-10=y\end{bmatrix}\\\\\mathrm{Isolate}\:x\:\mathrm{for}\:-8x+y=-32:\quad x=-\frac{-32-y}{8}\\\\\mathrm{Subsititute\:}x=-\frac{-32-y}{8}\\\begin{bmatrix}-3\left(-\frac{-32-y}{8}\right)-10=y\end{bmatrix}\\\\Simplify\\\begin{bmatrix}\frac{3\left(-32-y\right)}{8}-10=y\end{bmatrix}\\\\\mathrm{Isolate}\:y\:\mathrm{for}\:\frac{3\left(-32-y\right)}{8}-10=y:\quad y=-16\\\\\mathrm{For\:}x=-\frac{-32-y}{8}\\\\\mathrm{Subsititute\:}y=-16\\x=-\frac{-32-\left(-16\right)}{8}\\$

$-\frac{-32-\left(-16\right)}{8}=2\\x=2\\x=2,\:y=-16$

3 0

3 years ago

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Um someone help? But with real answers please

levacccp [35]

Answer:

answer is

Step-by-step explanation:

The number of students in order from least to greatest is 14<24<27<54

Step-by-step explanation:

Total students = 150

16% students play soccer

No. of students play soccer =

9/25 play basketball

No. of students play basketball =

play football

No. of students play football =

No. of students do not play anything = 14

The number of students in order from least to greatest is 14<24<27<54

6 0

3 years ago