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love history [14]
2 years ago
7

A multiple-choice examination has 10 questions, each with four possible answers, only one of which is correct. Suppose that one

of the students who takes the examination answers each of the questions with an independent random guess. What is the probability that he answers at least six questions correctly?​
Mathematics
1 answer:
Nata [24]2 years ago
8 0

Answer:

0.0197277

Step-by-step explanation:

Consider the random variable X 

Where X denotes the number of (success/having a correct answer)

in 10 identical and independent trials .

then

X follows the Binomial distribution with parameters 

10 and  p = p(success) = 1/4

p\left( X\geq 6\right)  =\sum^{10}_{k=6} p\left( X=k\right)

               =\sum^{10}_{k=6} C^{k}_{10}\left( \frac{1}{4} \right)^{k}  \left( \frac{3}{4} \right)^{10-k}

               =\frac{20686}{2^{20}} \\= 0.0197277

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Answer:

Step-by-step explanation:

Sounds as tho' possible answer choices were listed.  Please, share them without being asked to do so.  Thank you.

 7√(x²)          7√(x²)

------------- = ----------------------

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We want to get the fractional exponent out of the denominator.  To do this, multiply both numerator and denominator by y^(1/2):

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