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olasank [31]
2 years ago
15

Using the following image, solve for SR. Look at the image closely.

Mathematics
2 answers:
iren [92.7K]2 years ago
4 0

Step-by-step explanation:

I assume

SR = 2x + 23

RQ = x + 21

if that is true, then the situation is completely simple :

14 = (2x + 23) + (x + 21) = 3x + 44

3x = -30

x = -10

SR = 2×-10 + 23 = -20 + 23 = 3

RQ = -10 + 21 = 11

Vilka [71]2 years ago
4 0

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \:x = -10

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \: SR + RQ = SQ

\qquad \tt \rightarrow \: 2x + 23 + x + 21 = 14

\qquad \tt \rightarrow \: 3x + 44 = 14

\qquad \tt \rightarrow \: 3x = 14 - 44

\qquad \tt \rightarrow \: 3x =  - 30

\qquad \tt \rightarrow \: x =  - 10

Now,

\qquad \tt \rightarrow \: SR = 2x + 23

\qquad \tt \rightarrow \: SR = 2(-10) + 23

\qquad \tt \rightarrow \: SR =-20+ 23

\qquad \tt \rightarrow \: SR = 3 \:\: units

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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At what point on the paraboloid y = x2 + z2 is the tangent plane parallel to the plane 3x + 2y + 7z = 2? (if an answer does not
Nikitich [7]
If f(x, y, z) = c represent a family of surfaces for different values of the constant c. The gradient of the function f defined as \nabla f is a vector normal to the surface f(x, y, z) = c.

Given <span>the paraboloid

y = x^2 + z^2.

We can rewrite it as a scalar value function f as follows:

f(x,y,z)=x^2-y+z^2=0

The normal to the </span><span>paraboloid at any point is given by:

\nabla f= i\frac{\partial}{\partial x}(x^2-y+z^2) - j\frac{\partial}{\partial y}(x^2-y+z^2) + k\frac{\partial}{\partial z}(x^2-y+z^2) \\  \\ =2xi-j+2zk

Also, the normal to the given plane 3x + 2y + 7z = 2 is given by:

3i+2j+7k

Equating the two normal vectors, we have:
</span>
2x=3\Rightarrow x= \frac{3}{2}  \\  \\ -1=2 \\ \\ 2z=7\Rightarrow z= \frac{7}{2}

Since, -1 = 2 is not possible, therefore there exist no such point <span>on the paraboloid y = x^2 + z^2 such that the tangent plane is parallel to the plane 3x + 2y + 7z = 2</span>.
4 0
3 years ago
How many negative roots will this function have? f(x) = x^7 – 2x^4 + 7x^2 + 2x – 2<br> help plsss
Vikentia [17]

There are two negative roots to the provided polynomial function

f(x) = x⁷ – 2x⁴ + 7x² + 2x – 2

<h3>What is polynomial?</h3>

Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.

\rm a_1x+a_2x^2+a_3x^3+a_4x^4..........a_nx^n

We have a polynomial function:

f(x) = x⁷ – 2x⁴ + 7x² + 2x – 2

\rm f(x) =\left(x+1\right)\left(x^6-x^5+x^4-3x^3+3x^2+4x-2\right)

Using the zero product property:

\rm \left x+1\right = 0 \ \ \ or \left x^6-x^5+x^4-3x^3+3x^2+4x-2\right = 0

After solving:

x = -1, x = -0.853, and x = 0.418 (using the graph method)

Thus, there are two negative roots to the provided polynomial function

f(x) = x⁷ – 2x⁴ + 7x² + 2x – 2

Learn more about Polynomial here:

brainly.com/question/17822016

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2 years ago
An equation and the steps to solve it are shown below:
lisov135 [29]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Can someone please help me?
yaroslaw [1]
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2√384= 2√8^2*6 = 2*8√6 = 16√6

√96= √4^2*6 = 4√6

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Final answer: -14√6

4 0
3 years ago
What is m% of n? Please help!
melisa1 [442]

Answer:

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Step-by-step explanation:

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