3)
(x/3)+(2/5)
(5x/15)+(6/15)
(5x+6)/15
4)
(2/x)+(3/7)
(14/7x)+(3x/7x)
(3x+14)/(7x)
5)
(x/2)+(1/3)+(x/4)
(6x/12)+(4/12)+(3x/12)
(9x+4)/12
i would subtract 7 and divide by 4;
4x + 7 = 15
4x = 8
x = 2
Answer:
You are rocking this... This is correct! :D
Step-by-step explanation:
Please give me brainliest :)
Use compound interest formula F=P(1+i)^n twice, one for each deposit and sum the two results.
For the P=$40,000 deposit,
i=10%/2=5% (semi-annual)
number of periods (6 months), n = 6*2 = 12
Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253
For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
i=5% (semi-annual
n=2*(6-3), n = 6
Future value (at end of year 6)
F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913
Total amount after 6 years
= 71834.253 + 26801.913
=98636.17 (to the nearest cent.)
Answer:
2x+23
Step-by-step explanation:
