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TEA [102]
4 years ago
12

which of the following sets could not be the lengths of the sides of a triangle. {11,14, 25} {5, 6, 10} {4, 4, 5} {1, 2, 2}

Mathematics
1 answer:
NARA [144]4 years ago
6 0
A triangle is only possible if you can add any two sides and have the sum be larger than the third side. This happens with choice B, C, and D. 

With choice A, we have 11+14 = 25 not larger than the third side of 25. So a straight line is possible and it's not possible to draw a triangle with these dimensions. 

Answer: Choice A

note: This is using the triangle inequality theorem
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What’s the answer of a multiplying polynomials (3x-1) to the second power and (x+6) to the second power
Vladimir [108]

9x^4+102x^3+253x^2-204x+36 is the result of multiplying (3x-1) to the second power and (x+6) to the second power

<h3><u>Solution:</u></h3>

Given that we have to find the result of multiplying polynomials (3x-1) to the second power and (x+6) to the second power

"Second power" means the term is raised to power of 2

Therefore,

We have to multiply (3x-1)^2 \text{ and }(x+6)^2

\rightarrow (3x-1)^2 \times (x+6)^2

We can use the algebraic identity to expand the above expression

(a+b)^2 = a^2+2ab+b^2\\\\(a-b)^2=a^2-2ab+b^2

Applying these in above expression, we get

\rightarrow ((3x)^2-2(3x)(1)+1^2) \times (x^2+2(x)(6)+6^2)\\\\\rightarrow (9x^2-6x+1) \times (x^2+12x+36)

Multiply each term in first bracket with each term in second bracket

\rightarrow 9x^2(x^2)+(9x^2)(12x)+(9x^2)(36)-6x(x^2)-6x(12x)-6x(36) + x^2+12x+36

Simplify the above expression

\rightarrow 9x^4+108x^3+324x^2-6x^3-72x^2-216x+x^2+12x+36

Combine the like terms

\rightarrow 9x^4+102x^3+253x^2-204x+36

Thus the above expression is the result of multiplying (3x-1) to the second power and (x+6) to the second power

4 0
3 years ago
Plot and connect the points A(1,-5), B(-4,-3), C(3,-3), and find the area of the triangle it forms.
Dovator [93]

Answer:

  7 square units

Step-by-step explanation:

Two of the points are on the horizontal line y = -3, so it is convenient to call that the "base" of the triangle. The length of the base is the difference in the x-coordinates of its end points:

  b = 3 -(-4) = 7

The height is measured perpendicular to the base, so is the vertical distance from the line y=-3 to the third point. That distance is the difference between -3 and the y-coordinate of point A:

  -3 -(-5) = 2

The triangle has a base of length 7 and a height of 2. Its area is ...

  A = 1/2bh

  A = 1/2(7)(2) = 7 . . . . square units

6 0
2 years ago
PLZZ help meee and I will give brainliest
serious [3.7K]
A.. is the answer! Have a good day/night
4 0
2 years ago
A total of 460 tickets were sold for the school play. The tickets were either adult or student. The number of student tickets so
larisa [96]

Answer:

153 should be your awnser

4 0
4 years ago
What is the equation of the line that passes through the points (-3,0.5) and (3,-0.5)
MakcuM [25]

Answer:

y = -1/6x + 0

Step-by-step explanation:

Using the equation of line

y_2 - y_1 / x_2 - x_1 = y - y_1 / x_1

Using the information we are provided with

( -3, 0.5)(3 , -0.5)

y_1 = 0.5

x_1 = -3

x_2 = 3

y_2 = -0.5

-0.5 - 0.5 / 3- (-3) = y - 0.5 / x - (-3)

-0.5 - 0.5 / 3 +3 = y - 0.5 / x + 3

-1 / 6 = y - 0.5 / x + 3

Cross multiply

-1(x + 3) = 6(y - 0.5)

Open the brackets

-x - 3 = 6y - 3

-x - 3 + 3 = 6y

-x + 0 = 6y

Divide through by 6 to get y

Following the eqn y = mx + C

-x + 0 / 6 = 6y / 6

y = -x + 0 / 6

We can separate it

y = -x / 6 + 0/6

y = -1/6x + 0

Therefore, the equation of the line is

y = -1/6x + 0

7 0
3 years ago
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