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alex41 [277]
2 years ago
7

A parabola opens upward. The parabola goes through the point (3, -1), and the vertex is at (2, -2). What are the values of h and

v? To find the value of a, subtract the y-coordinate of the vertex from the y coordinate of the point on the parabola that is 1 unit to the right of the vertex. Find the value of A for the parabola
Mathematics
1 answer:
Korolek [52]2 years ago
7 0

The value of a is 1/4 and the value of h and k is (2,-7/4)

<h3>What is a Parabola ?</h3>

A parabola is a u shaped curve. It is a plane curve whose all points are at a fixed distance form a point called focus.

(x-h)² = 4a(y-k)

It is given that the parabola goes through the point (3, -1), and the vertex is at (2, -2).

Therefore
(x -2)² = 4a(y +2)

The parabola passes through the point (3,-1)

(3-2)² = 4*a(-1+2)

1 = 4 a

a = 1/4

Now to determine the value of focus point , (h,k)

(h = 2)

k = - 2 +1/4 = -7/4

Therefore The value of a is 1/4 and the value of h and k is (2,-7/4)

To know more about Parabola

brainly.com/question/4074088

#SPJ1

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Answer:

Yes lines are intersecting, point of intersection is <4,2,0>.

Step-by-step explanation:

Given parametric equations of line are:

r_{1}(t) =  + t  \\ r_{1}(t) = \\ r_{1}(t) = ---(1)

r_{2}(s) =  + s \\ r_{2}(s) = \\ r_{2}(s) = ---(2)\\

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Considering A and B to find values of t and s

From A

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This shows lines are intersecting.

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Putting s=1 in (2)

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Point of intersection is <4,2,0>.

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