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agasfer [191]
3 years ago
5

-(-10x-8)=-(4x+10) A)-4 B)-2 C)-3 D)3 show work

Mathematics
1 answer:
Eva8 [605]3 years ago
4 0

Answer:

<h3>             None of given </h3><h3>                  x = -1²/₇ </h3>

Step-by-step explanation:

-(-10x - 8) = -(4x + 10)

  10x + 8 = -4x - 10

      -8            -8

     10x  =  -4x - 18

      +4x     +4x

     14x = -18

      ÷14    ÷14

      x = -¹⁸/₁₄ = -⁹/₇ = -1²/₇

I think you meant -(10x-8)=-(4x+10)

Then:

-(10x - 8) = -(4x + 10)

  -10x + 8 = -4x - 10

      -8            -8

     -10x  =  -4x - 18

       +4x     +4x

     -6x  =  -18

      ÷(-6)    ÷(-6)

<h3>         x = 3     D)</h3>
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(3,-2) (4,5)<br> m = [?]
Elan Coil [88]

Answer:

m = 7

Step-by-step explanation:

Use the slope formula.

m=\frac{rise}{run}=\frac{y_2-y_1}{x_2-x_1}=\frac{5+2}{4-3}=\frac{7}{1}=\boxed{7}

The slope is 7.

Hope this helps.

8 0
3 years ago
Read 2 more answers
Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe
nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let D^c be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that  one person in 10,000 people has a rare genetic disease.

So,P(D)=\frac{1}{10000}

Only 0.4% of the people who don't have it test positive.

P(A|D^c) = probability that a person is tested positive given he don't have a disease = 0.004

P(D^c)=1-\frac{1}{10000}

Formula:P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}

P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}

P(D|A)=\frac{2470}{2471}=0.9995

P(D|A)=0.9995

A)The probability that someone who tests positive has the disease is 0.9995

(B)

P(D^c|A^c)=probability that someone does not have disease given that he tests negative

P(A^c|D^c)=probability that a person tests negative given that he does not have disease =1-0.004

=0.996

P(A^c|D)=probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}

P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}

P(D^c|A^c)=0.99999

B)The probability that someone who tests negative does not have the disease is 0.99999

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3 years ago
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2 years ago
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Slav-nsk [51]

Answer:

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7 0
3 years ago
Read 2 more answers
There are two cubes, one smaller than the other. The two cubes combined has a volume of 118.125in. Find the side length of each
Sunny_sXe [5.5K]

Step-by-step explanation:

let the big cube side be b

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17 b^3/8 = 118.125

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