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kolezko [41]
1 year ago
11

What is lim x->3 x^2+x-12/x^2-3x 0 7/3 4 DNE

Mathematics
1 answer:
Sholpan [36]1 year ago
8 0

It looks like the limit is

\displaystyle \lim_{x\to3} \frac{x^2 + x - 12}{x^2 - 3x}

Factorize the numerator and denominator to reveal a removable discontinuity and evaluate the limit.

\displaystyle \lim_{x\to3} \frac{x^2 + x - 12}{x^2 - 3x} = \lim_{x\to3} \frac{(x + 4) (x - 3)}{x (x - 3)} = \lim_{x\to3} \frac{x+4}x = \frac{3+4}3 = \boxed{\frac73}

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