86 *2 = 172
172/3 = 57.33
54 + 56 +58 =168
168/2 =84
56 + 58 +60 = 174
174/2 =87
58 +60 +62 = 180
180/2 = 90
60 +62 +64 = 186
186/2 = 93
62 +64+66 = 192
192/2 = 96
there are 3 sets of numbers that fall between 84 & 96
1 set equals 84 and 1 set equals 96
so if you are counting those there are 5 sets
2/11 ≈ 0.18 3/12 = 0.25.
So the answer is no, 2/11 isn't bigger than 3/12.
I hope this helps!
Hello :
f(x) = (x-5)(x+2i)
= x² +2ix -5x-10i
f(x) = x² +(2i-5)x -10i
<span>coefficients : a =1 b = 2i-5 c =-10i</span>
Answer:
Step-by-step explanation:
Simply multiply 2m both sides:
A = (9+H)(2m)
Hope this helps!
