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kompoz [17]
3 years ago
11

In each of the following equations, find all the integers x satisfying the equation:

Mathematics
1 answer:
Nuetrik [128]3 years ago
8 0

Answer:

b

Step-by-step explanation:

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The table shows the age, in years, of employees in a company.
joja [24]

Answer:

a) The modal class for this case represent the class with the highest frequency

And for this case would be 24 with the highest frequency 8

b) \bar X = \frac{19*3 + 21*2 + 23*7 +25*8}{3+2+7+8} =23

Step-by-step explanation:

Part a

The modal class for this case represent the class with the highest frequency

And for this case would be 24 with the highest frequency 8

Part b

For this case we need to find the mid point of each interval:

Interval   Midpoint  Frequency

18-20          19                 3

20-22         21                 2

22-24         23                 7

24-26         25                 8

And we can find the sample mean with this formula:

\bar X = \frac{\sum_{i=1}^n f_i x_i}{n}

And replacing we got:

\bar X = \frac{19*3 + 21*2 + 23*7 +25*8}{3+2+7+8} =23

4 0
3 years ago
Please help me out!!!!!!!!
qaws [65]

Answer:

x = - 6

Step-by-step explanation:

Given that y varies directly as x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition y = - 9 when x = 3, thus

k = \frac{y}{x} = \frac{-9}{3} = - 3

y = - 3x ← equation of variation

When y = 18, then

18 = - 3x ( divide both sides by - 3 )

x = - 6

5 0
3 years ago
The area of a circle is 50.24 square yards. What is the circle's radius?
Marina CMI [18]

Answer:

Radius=4yd

Step-by-step explanation:

4 0
3 years ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
Identify each function as linear, quadratic, or exponential. ƒ(x) = 4x2 g(x) = 1 - x h(x) = 32x
DaniilM [7]

Answer:

f(x) is quadratic. g(x) and h(x) are linear.

Step-by-step explanation:

So we have the three functions:

f(x)=4x^2\\g(x)=1-x\\h(x)=32x

Linear functions are polynomials in which the highest degree is 1.

Quadratic functions are polynomials in which the highest degree is 2.

And exponential functions usually have a variable in the exponent (e.g. 2^x).

For f(x), the highest degree is 2. Thus, f(x) is a quadratic function.

For g(x), the highest degree is 1 and there are no variables in the exponent. Thus, g(x) is a linear function.

Similarly, for h(x), the highest degree is 1 and there are no variables in the exponents, so h(x) is also a linear function.

5 0
4 years ago
Read 2 more answers
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