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ankoles [38]
2 years ago
15

A bag contains 20 identical balls of which 12 are white and 8 are black in colour. 3 balls are drawn randomly without any replac

ement. what is the probability of picking 2 white balls and 1 black ball?
Mathematics
1 answer:
Kaylis [27]2 years ago
7 0

The probability of picking 2 white balls and 1 black ball is 0.154

<h3>How to determine the probability?</h3>

The given parameters are:

  • Number of balls, n = 20
  • White = 12
  • Black = 8

When each ball is selected, the total number of ball decreases by 1 and the type of ball also decreases.

So, the probability is represented as:

P(2 white and 1 black) = White/n * White - 1/n - 1 * Black//n - 2

Substitute known values

P(2 white and 1 black) = 12/20 * 11/19 * 8//18

Evaluate

P(2 white and 1 black) = 0.154

Hence, the probability of picking 2 white balls and 1 black ball is 0.154

Read more about probability at:

brainly.com/question/251701

#SPJ1

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Assume that we have two events, and , that are mutually exclusive. Assume further that we know and . If an amount is zero, enter
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Explained below.

Step-by-step explanation:

The complete question is:

Assume that we have two events, A and B, that are mutually exclusive. Assume further that we know P(A) = 0.30 and P(B) =0.40.

What is P(A and B)?

What is P(A | B)?

Is P(A | B) equal to P(A)?

Are events A and B dependent or independent?

A student in statistics argues that the concepts of mutually exclusive events and independent events are really the same, and that if events are mutually exclusive they must be independent. Is this statement accurate?

What general conclusion would you make about mutually exclusive and independent events given the results of this problem?

Solution:

The probability of the two events <em>A</em> and <em>B</em> are:

P(A) = 0.30 and P(B) =0.40

(a)

Compute the value of P (A ∩ B) as follows:

P(A\cap B)=0

This is because mutually exclusive events are those events that cannot occur together.

(b)

Compute the value of P (A | B) as follows:

P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{0}{0.40}=0

Thus, the value of P (A | B) is 0.

(c)

No, P (A | B) is not equal to the P (A).

(d)

As mentioned in part (a), mutually exclusive events are those events which cannot occur together.

That is, P(A\cap B)=0.

Events A and B are independent  if the chance of their concurrent happening is equivalent to the multiplication of their distinct probabilities.

That is, P(A\cap B)=P(A)\times P(B).

The concepts of mutually exclusive events and independent events are not the same.

(e)

As the it is provided that A and B are mutually exclusive events, we know that P(A\cap B)=0.

Now compute the value of P(A)\times P(B) as follows:

               P(A)\times P(B)=0.30\times 0.40=0.12\neq 0

Thus, the events A and B are not independent.

Thus, if two events are mutually exclusive events they cannot be independent.

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