Answer:
3/4
Step-by-step explanation:
We want to find the probability that a student has a dog given that they have a cat, this means that the information given from the side that says " does not have a cat " is irrelevant and we only look at the information from the side that says " has a cat "
Probability = favorable outcomes / total # of outcomes
Favorable outcomes = Having a cat and dog , 6 students have both a cat and dog so favorable outcomes = 6
Total # of outcomes = total # of students that have a cat whether they have a dog or not. Total # of tudents that have a cat = 6 + 2 = 8
So probability of having a dog given that they have a cat = 6/8 or 3/4
Answer:
Step-by-step explanation:
I think I stays the same 5/6
Answer:
a. 1,000 yards
b. (2, -1)
Step-by-step explanation:
Coordinates of Ben's House = (6, 2)
Coordinates of Kate's House = (-2, -4)
a. Number of yards between Kate and Ben's House using instance formula,
.





1 unit = 100 yards
Therefore, 10 units = 1,000 yards.
Kate and Ben's House are 1,000 yards apart.
b. Since Jason's home is halfway between Ben and Kate's House, therefore, Jason's location is the midpoint between Ben and Kate's House. Use the midpoint formula to calculate the coordinates of Jason's location on the map, using (6, 2) and (-2, -4).

Plug in the values



Answer:
f(x) = 16x2 + 32x - 9
To find the "zeros", set f(x) = 0:
0 = 16x2 + 32x - 9
The equation is solvable by factoring or by using the quadratic formula. The factors (use the "ac" method) are:
0 = (4x-1)(4x+9)
x = 1/4 = 0.25 and x = -9/4 = -2.25
Step-by-step explanation: