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antoniya [11.8K]
2 years ago
12

Multiply (5x−8) (2x+4)

Mathematics
2 answers:
natka813 [3]2 years ago
8 0

Answer:

10x^{2}+4x-32

Step-by-step explanation:

5x times 2x =10x^{2}

5x times 4 = 20x

-8 times 2x = -16x

-8 times 4 =-32

10x^{2} +20x - 16x - 32

20x -16x = 4x

10x^{2} + 4x - 32

irga5000 [103]2 years ago
6 0

Answer:

10x^2 + 4x - 32

<em>I hope this helps :)</em>

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Is the equation below written in standard form? If not, select which explanation best applies to why the equation
natita [175]

Answer:

D

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers

12 = 2x + 4y , that is

2x + 4y = 12 ← is in standard form

8 0
3 years ago
A student was asked to find the equation of the tangent plane to the surface z=x3−y4 at the point (x,y)=(1,3). The student's ans
aliya0001 [1]

Answer:

C) The partial derivatives were not evaluated a the point.

D) The answer is not a linear function.

The correct equation for the tangent plane is z = 241 + 3 x - 108 y or  3x-108y-z+241 = 0

Step-by-step explanation:

The equation of the tangent plane to a surface given by the function S=f(x, y) in a given point (x_0, y_0, z_0) can be obtained using:

z-z_0=f_x(x_0,y_0,z_0)(x-x_0)+f_y(x_0,y_0, z_0)(y-y_0)   (1)

where f_x(x_0, y_0, z_0) and f_y(x_0, y_0, z_0) are the partial derivatives of f(x,y) with respect to x and y respectively and evaluated at the point (x_0, y_0, z_0).

Therefore we need to find two missing inputs in our problem in order to use equation (1). The z_0 coordinate and the partial derivatives f_x(x_0, y_0, z_0) and f_y(x_0, y_0, z_0). For z_0 just evaluating in the given function we obtain z_0= -80 and the partial derivatives are:

\frac{\partial f(x,y)}{\partial x} \equiv f_x(x, y)= 3x^2 \\f_x(x_0, y_0) = f_x(1, 3) = 3

\frac{\partial f(x,y)}{\partial y} \equiv f_y(x, y)= -4y^3 \\f_y(x_0, y_0) = f_y(1, 3) = -108

Now, substituting in (1)

z-z_0=f_x(x_0,y_0,z_0)(x-x_0)+f_y(x_0,y_0, z_0)(y-y_0)\\z + 80 = 3x^2(x-1) - 4y^3(y-3)\\z = -80 + 3x^2(x-1) - 4y^3(y-3)

Notice that until this point, we obtain the same equation as the student, however, we have not evaluated the partial derivatives and therefore this is not the equation of the plane and this is not a linear function because it contains the terms (x^3 and y^4)

For finding the right equation of the tangent plane, let's substitute the values of the partial derivatives evaluated at the given point:

z = -80 + 3x^2(x-1) - 4y^3(y-3)\\z = -80 +3(x-1)-108(y-3)\\z = 241 + 3 x - 108 y

or 3x-108y-z+241 = 0

7 0
3 years ago
Scarlett stopped at a campground along the Appalachian trail. The campground had a 1 2 acre area for tents, which was divided in
Juli2301 [7.4K]

Answer:

Each tent site is 1/12 acre

Step-by-step explanation:

1/2 acre for tents divided by 6

1/2 ÷6

Copy dot flip

1/2 * 1/6

1/12

Each tent site is 1/12 acre

7 0
3 years ago
Read 2 more answers
If y varies directly as x, and y = 7 when x =4, find y when x = 16.<br> y =
Allushta [10]

Answer:

y=28

Step-by-step explanation:

y=kx

7=k4

7/4=k

y=kx

y=7/4 x16

=7x4

=28

5 0
3 years ago
if a pair of six-sided dice, with sides numbered through 6, is tossed, what is the probability that the sum of the two numbers i
Ray Of Light [21]

|\Omega|=6^2=36\\&#10;|A|=3\\\\&#10;P(A)=\dfrac{3}{36}=\dfrac{1}{12}\approx8\%

3 0
3 years ago
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