Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:

Hence the bounds of the interval are found as follows:


The 95% confidence interval is (0.2316, 0.3112).
More can be learned about the z-distribution at brainly.com/question/25890103
Answer:
n ≥ -17
Step-by-step explanation:
Writing a symbolic inequality, we get:
10 - 3n ≤ 61
Solve this for 3n by adding 3n to both sides of this equation:
10 ≤ 61 + 3n
Solve for n by subtracting 61 from both sides and then dividing all of the resulting terms by 3:
-51 ≤ 3n (divide both sides by 3):
-17 ≤ n, or
n ≥ -17
Answer:
$40.25 per hour
Step-by-step explanation:
If you multiply 35 by 15% you get 5.25. You can either add this on, or you can multiply by 1.15 instead of .15.