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deff fn [24]
1 year ago
8

le="\sf\large\green{\underbrace{\red{Question*}}}:" alt="\sf\large\green{\underbrace{\red{Question*}}}:" align="absmiddle" class="latex-formula">
Factorize
4 {a}^{2}  -  \frac{ {y}^{2} }{16}
​
Mathematics
1 answer:
astraxan [27]1 year ago
6 0

Answer:

(2a - \frac{y}{4} )(2a + \frac{y}{4} )

Step-by-step explanation:

4a² - \frac{y^2}{16} ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

4a² - \frac{y^2}{16}

= (2a)² - (\frac{y}{4} )²

= (2a - \frac{y}{4} )(2a + \frac{y}{4} )

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(1.35)(27)= 36.45(0) = 0 (13) = 13
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The ratio of pencils to erasers is 4:1. If there are 20 pencils, how many erasers are there.
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2 years ago
In a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of th
11111nata11111 [884]

Answer:

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Step-by-step explanation:

We are given that in a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of the students passed both exams.

Let Probability that the students passed the first exam = P(F) = 0.74

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Now, if the student passed the first exam, probability that he passed the second exam is given by the conditional probability of P(S/F) ;

As we know that conditional probability, P(A/B) = \frac{P(A\bigcap B)}{P(B) }

Similarly, P(S/F) = \frac{P(S\bigcap F)}{P(F) } = \frac{P(F\bigcap S)}{P(F) }  {As P(F \bigcap S) is same as P(S \bigcap F) }

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Therefore, probability that he passed the second exam is 0.784 .

5 0
3 years ago
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