x − y = 0 = difference
x + y = 4 = sum
Can be solved by the sum and difference rule (most of the time without pen and paper)
x=(sum+difference)/2=0+4/2=2
y=(sum-difference)/2=(4-0)/2=2
Hi there
-5i + 5-1 + 6
= -5i + 11- 1
= 5i + 10
That's the answer :0
I hope that's help... Do you have any question ?
Answer:
b+6
Problem:
If the average of b and c is 8, and d=3b-4, what is the average of c and d in terms of b?
Step-by-step explanation:
We are given (b+c)/2=8 and d=3b-4.
We are asked to find (c+d)/2 in terms of variable, b.
We need to first solve (b+c)/2=8 for c.
Multiply both sides by 2: b+c=16.
Subtract b on both sides: c=16-b
Now let's plug in c=16-b and d=3b-4 into (c+d)/2:
([16-b]+[3b-4])/2
Combine like terms:
(12+2b)/2
Divide top and bottom by 2:
(6+1b)/1
Multiplicative identity property applied:
(6+b)/1
Anything divided by 1 is that anything:
(6+b)
6+b
b+6
Answer:
A) 8 treatments
- Normal sleeper, high school dropout
- Normal sleeper, high school graduate
- .Normal sleeper, college graduate
- Chronic insomnia, college graduate
- Chronic insomnia, high school graduate
- Chronic insomnia, high school dropout
- Normal sleeper, some college
- Chronic insomnia, some college
B) 8 treatments
Step-by-step explanation:
<u>A) determine the number of treatments for this study </u>
The number of treatments for this study can be determined as : 2 * 4 = 8 treatments
and they are :
- Normal sleeper, high school dropout
- Normal sleeper, high school graduate
- .Normal sleeper, college graduate
- Chronic insomnia, college graduate
- Chronic insomnia, high school graduate
- Chronic insomnia, high school dropout
- Normal sleeper, some college
- Chronic insomnia, some college
B) eight (8 ) treatments
Answer: 1/5
Step-by-step explanation:
