<em>The</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>2</em><em>5</em><em>.</em>
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>.</em>
<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>helpful</em><em> </em><em>to</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
<em>~</em><em>p</em><em>r</em><em>a</em><em>g</em><em>y</em><em>a</em>
Answer:
The Answer is that X = 10
Step-by-step explanation:
Given Points: (2, 3) and (x, 6)
Given Slope, m = 3/4
Use the Point Slope form and solve for x:
y - y1 = m(x - x1)
3 - 6 = 3/4(2 - x)
-6 = 6/4 - 3/4x
-6 - 6/4 = -3/4x
-24/4 - 6/4 = -3/4x
30/4 = -3/4x
(-4/3)(30/4) = x
-120/12 = x
10 = x
Proof:
m = y - y1/(x - x1)
m = 3 - 6/(2 - 10)
m = -6/-8
m = 3/4
Hope this Helps! Have an Awesome Day!!
So basically you know that 25 x 17 is 425. So all you would do is estimate! It's super simple. Just do 25 x 17, then put your estimate in the estimate box. 5 or higher it goes up, 4 or lower it goes down, so for your estimate I would probably put 430. Hope this helps! :)
Answer:
16 km due west
Step-by-step explanation:
The bearing of the school p from school q is 16 km due west.
To find the bearing of school q from school p, we have to find the direction that the school q is with respect to school p.
Since p is directly west of q, then it implies that q must be directly east of p.
We now know the direction.
Since the distance from q to p is exactly the same as the distance from p to q, then, the distance from p to q is 16 km.
Hence, the bearing of q from p is 16 km due west.
In right angle triangle cot(x) = base÷perpendicular
~ 5/12
