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3 years ago

Use Pascal’s Triangle to determine the fifth term of the expansion of (x + 3)7

Mathematics

1 answer:

ValentinkaMS [17]3 years ago

7 0

Answer:

2835x^5.

Step-by-step explanation:

By Binomial Theorem, T(r+1) = nCr * a^(r+1) * b^r.

Term 5 = 7C4 * x^5 * 3^4

= 35 * x^5 * 3^4

= 2835x^5.

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2) Solve the following equation for x: 2(x-5) = 36<br> A) 15.5 В) 23 С) 18<br> D) 13

Irina-Kira [14]

Answer:

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

The port of South Louisiana, located along 54 miles of the Mississippi River between New Orleans and Baton Rouge, is the largest

Ksenya-84 [330]

Answer:

a) 0.7287

b) 0.9663

c) 0.237

d) 3.65 tons of cargo per week or more that will require the port to extend its operating hours.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 4.5 million tons of cargo per week

Standard Deviation, σ = 0 .82 million tons

We are given that the distribution of number of tons of cargo handled per week is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P( port handles less than 5 million tons of cargo per week)

P(x < 5)

$P( x < 5) = P( z < \displaystyle\frac{5 - 4.5}{0.82}) = P(z < 0.609)$

Calculation the value from standard normal z table, we have,

$P(x < 5) =0.7287= 72.87\%$

b) P( port handles 3 or more million tons of cargo per week)

$P(x \geq 3) = P(z \geq \displaystyle\frac{3-4.5}{0.82}) = P(z \geq −1.82926)\\\\P( z \geq −1.82926) = 1 - P(z < -1.829)$

Calculating the value from the standard normal table we have,

$1 - 0.0337 = 0.9663 = 96.63\%\\P( x \geq 3) = 96.63\%$

c)P( port handles between 3 million and 4 million tons of cargo per week)

$P(3 \leq x \leq 4) = P(\displaystyle\frac{3 - 4.5}{0.82} \leq z \leq \displaystyle\frac{4-4.5}{0.82}) = P(-1.829 \leq z \leq -0.609)\\\\= P(z \leq -0.609) - P(z < -1.829)\\= 0.271-0.034 = 0.237= 23.7\%$

$P(3 \leq x \leq 4) = 23.7\%$

d) P(X=x) = 0.85

We have to find the value of x such that the probability is 0.85.

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 4.5}{0.82})=0.85$

$= 1 -P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.85$

$=P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.15$

Calculation the value from standard normal z table, we have,

$P( z \leq -1.036) = 0.15$

$\displaystyle\frac{x - 4.5}{0.82} = -1.036\\x = 3.65$

Thus, 3.65 tons of cargo per week or more that will require the port to extend its operating hours.

8 0

2 years ago

What is the area of triangle below?

kenny6666 [7]

Answer:

Step By Step Explanation:

7×4/2

=7×2

=14

Have a nice day! :)

-Vana

7 0

2 years ago

A polynomial function has zeros -1, 2, and 7 (all multiplicity 1). Write a function in standard form that could represent this f

Hoochie [10]

Answer:

Step-by-step explanation:

(x+1)(x-2)(x-7)

x^3-8x^2+5x+14

7 0

2 years ago

Complete the equation of the line through (-6,5)(−6,5)left parenthesis, minus, 6, comma, 5, right parenthesis and (-3,-3)(−3,−3)

sladkih [1.3K]

Answer:

The equation of the line passing through the given points is:

$y=-\frac{8}{3}x-11$

Step-by-step explanation:

Given:

The two points are: $(x_1,y_1)=(-6,5)\textrm{ and }(x_2,y_2)=(-3,-3)$

The equation of a line when two points are given is:

$y-y_1=\left (\frac{y_2-y_1}{x_2-x_1} \right )(x-x_1)$

Plug in all the values and simplify.

$y-5=\left (\frac{-3-5}{-3-(-6)} \right )(x-(-6))\\y-5=\left (\frac{-8}{-3+6} \right )(x+6)\\y-5=\left (\frac{-8}{3} \right )(x+6)\\y-5=\frac{-8}{3}x-16\\y=\frac{-8}{3}x-16+5\\\\y=-\frac{8}{3}x-11$

Therefore, the equation of the line passing through the above points is

$y=-\frac{8}{3}x-11$

7 0

2 years ago