Use Pascal’s Triangle to determine the fifth term of the expansion of (x + 3)7
1 answer:
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Answer:
cos x ≠ 0 ⇔ x ≠ ; k ∈ N
<=> cos²x + sin²x = 1
⇔ 1 = 1
=> x = { R \ (pi/2 + k.pi); k ∈ N}
Step-by-step explanation:
Answer:
cos x ≠ 0 ⇔ x ≠ ; k ∈ N
<=> cos²x + sin²x = 1
⇔ 1 = 1
=> x = { R \ (pi/2 + k.pi); k ∈ N}
Step-by-step explanation: