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2 years ago

Can someone please explain how i do this

Mathematics

2 answers:

lukranit [14]2 years ago

8 0

Answer:

base: 4

exponent: 3

numerator: 1

denominator: 64

Step-by-step explanation:

4^4 * 4^-2: Here you subtract 2 from 4 (just basic rules)

so you get 4^2/4^5

4^2/4^5: you subtract 5 from 2 (also basic rules)

then you would get 4^-3

To put in positive exponents you do 1/4^3

which gets you 1/64

julsineya [31]2 years ago

8 0

Base: 4 exponent: 3 this is all I got

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2? It says it in the question I think

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3 years ago

On the coordinate plane below, Point P is located at (2,-3), and point Q is located at (-4,4).

nadezda [96]

Answer:

Step-by-step explanation:

We can use the distance formula

d = sqrt ( ( y2-y1)^2 + ( x2-x1) ^2)

d = sqrt ( ( 4- -3)^2 + ( -4 -2) ^2)

= sqrt ( ( 7^2 + ( -6)^2)

= sqrt( 49+ 36)

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5 0

3 years ago

Will give brainliest

pychu [463]

Answer:

Since the only numbers that are not 0 appear in the groups 5 < d ≤ 10 to 30 < d ≤ 35 the range is 5 < d ≤ 35.

8 0

3 years ago

A King in ancient times agreed to reward the inventor of chess with one grain of wheat on the first of the 64 squares of a chess

maxonik [38]

Answer:

Total weight of the wheat placed on 45th square will be = $1.26\times 10^{6}tons$

Step-by-step explanation:

King rewarded the inventor of chess by giving grain of wheat on every square of the chess board. He places one grain of wheat on first square, 2 on second, 4 on 3rd, 8 on 4th and so on.

In fact he places grains of wheat in a progression S = 1, 2, 4, 8, 16.........n terms where value of n is 64.

We can rewrite the progression as S = 2°, 2, 2², 2³,.........n terms (n = 64)

In a geometric progression we know the nth term = $a(r^{n-1})$

where a = first term of the series, r = common ratio, n = number of terms

Now we have to calculate the weight of all wheat placed on 45th square.

So we will put the values in the given formula 45th term =

$1\times (2^{45-1})$ = $2^{44}$ = $1.76\times 10^{13}$

Then the weight of wheat will be = $2.51\times 10^{9}pounds$ = $1.26\times 10^{6}tons$

7 0

3 years ago

In a experiment, the probability that event A occurs is 5/9, the probability that event B occurs is 5/7, and the probability tha

Ymorist [56]

Answer:

52.5% probability that A occurs given B occurs

Step-by-step explanation:

Suppose we have two events, A and B, the conditional probability formula is:

$P(A|B) = \frac{P(A \cap B)}{P(B)}$

In which

P(A|B) is the probability of A happening given that B happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(B) is the probability of B happening.

In this problem, we have that:

$P(A \cap B) = \frac{3}{8}, P(B) = \frac{5}{7}$

$P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{\frac{3}{8}}{\frac{5}{7}} = 0.525$

52.5% probability that A occurs given B occurs

7 0

3 years ago

Can someone please explain how i do this​

Can someone please explain how i do this