How do I graph this ?
1 answer:
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The nth term is
an=a1(r)^(n-1)
an=1(2)^(n-1)
a1=1
r=2
the sum of a geometric seequence is
a1=1
r=2
we want to find
(since we minus 1, the highest exponet is 9 so add 1 to make it correct)
an=a1(r)^(n-1)
an=1(2)^(n-1)
a1=1
r=2
the sum of a geometric seequence is
a1=1
r=2
we want to find
i)50
<u>Steps</u>
30+20=50
ii)7
<u>Steps</u>
75-(30+20)-18
=75-(50)-18
=7
iii)20
<u>Steps</u>
From the available data from the question
iv)30
<u>Steps</u>
From the available data from the questionl
v)From the attcged image file
