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2 years ago

Evaluate 2b^3 where b = 3

Mathematics

2 answers:

Dahasolnce [82]2 years ago

7 0

Answer:

$\mathrm{54=== > Ans.}$

Step-by-step explanation:

Hi student, let me help you out!

.........................................................................................

To evaluate (find the value) of this expression, we need to stick in the value of b, which is 3: $\mathtt{2(3)^3}$ .

The next operation is to cube 3 (multiply 3 times itself 3 times, or $\mathtt{3\times3\times3=27}$ .

Now let's multiply 2 times 27, which gives us an answer of $\boxed{\boxed{\boxed{\mathtt{54\:is\:the\:ans.}}}}$

Hope this helped you out! Ask in comments if even the slightest queries arise.

Best Wishes!

$\star\bigstar\underline{\underline{\overline{\overline{\textsf{Reach far. Aim high. Dream big.}}}}}\bigstar\star$

$\underline{\rule{300}{5}}$

densk [106]2 years ago

6 0

Answer:

Answer=54

Step-by-step explanation:

Given:- b=3

2b³

Solution:-

2 x b³

2 x 3 x 3 x 3

6 x 9

54 (answer)

Hope this helps you

Have a good day.

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Let $f(x) = x^2 + 4x - 31$. for what value of $a$ is there exactly one real value of $x$ such that $f(x) = a$?

enot [183]

To solve for this, we need to find for the value of x when the 1st derivative of the equation is equal to zero (or at the extrema point).

So what we have to do first is to derive the given equation:

f (x) = x^2 + 4 x – 31

Taking the first derivative f’ (x):

f’ (x) = 2 x + 4

Setting f’ (x) = 0 and find for x:

2 x + 4 = 0

x = - 2

Therefore the value of a is:

a = f (-2)

a = (-2)^2 + 4 (-2) – 31

a = 4 – 8 – 31

a = - 35

7 0

3 years ago

Suppose you work in the quality assurance department of a chemical processing plant and it is your responsibility to ascertain w

aleksandrvk [35]

Answer:

48.668 ≤ μ ≤ 63.332

Step-by-step explanation:

Given the data:

Sample (X) : 71, 45, 54, 75, 50, 49, 63, 55, 48, 50

Number of samples (n) = 10

α = 95% = 0.05

Determine the range within which the true mean of the fluid samples from the day shift will be with a 95% confidence

True mean = μ

Confidence interval :

m ± t(α/2 ; df) * s/√n

m - t(α/2 ; df) * s/√n ≤ μ ≤ m + t(α/2 ; df) * s/√n

m = sample mean ; s = sample standard deviation ; df = degree of freedom =(n - 1) = (10 - 1) = 9

Calculating the sample mean and standard deviation using calculator to save computation time :

71, 45, 54, 75, 50, 49, 63, 55, 48, 50

m = 56 ; s = 10.25

m - t(0.05/2 ; 9) * s/√n ≤ μ ≤ m + t(0.05/2 ; df) * s/√n

From t table : t(0.05/2 ; 9) = t(0.025, 9) = 2.262

56-2.262 * (10.25/√10) ≤ μ ≤ 56+2.262 * (10.25/√10)

48.668 ≤ μ ≤ 63.332

6 0

3 years ago

i used the answer key to get my answer and checked it with my dumb useless teacher and it’s right but, he won’t tell me how to g

gizmo_the_mogwai [7]

You multiply it with the same number you use for the denominator.
in this case 3/4 and 7/10
you find the LCM of the denominator is 20
so for 4 to become 20 you multiply by 5 then for the numerator 3 also multiply by 5, so you get 15/20
its the same also with 7/10, you multiply both the numerator and the denominator by 2 and get 14/20
hope it help... :)

7 0

3 years ago

PLEASE HELP !!!!! Solve. y +30 < 15

Troyanec [42]

Hello there! y < -15

To solve, isolate y. To do this, subtract 30 from both sides of the equation.

y + 30-30 < 15-30

y < -15

This is your final answer. The statement is saying that y must be less than -15 when you add 30 to it for your final answer to be less than 15.

I hope this was helpful and have a great rest of your day! :)

5 0

3 years ago

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Ben needs to run 3 kilometers. He already ran 1,200 meters. How much farther does he need to run?

Tanya [424]

1800 meters or 1.8 kilometers

7 0

3 years ago