Answer:
35
Step-by-step explanation:
The way I know is because I memorized every square up to 33.
BUT that's probably not helpful to you.
Remember that every perfect square has an odd number of factors. I'm not going to list them all out, but the factors of 35 are 1, 5, 7, and 35, giving it an even number of factors. All the rest have an odd number of factors because of the property of a perfect square: a number times itself gives a perfect square, but that number only counts as 1 factor.
Answer:
<AFB
Step-by-step explanation:
Answer:
The nth term in the sequence is given by the equation:

Step-by-step explanation:
Arranging a table for n and nth:
![\left[\begin{array}{ccc}n&nth\\1&1\\2&3\\2&16\\4&125\\5&1296\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dn%26nth%5C%5C1%261%5C%5C2%263%5C%5C2%2616%5C%5C4%26125%5C%5C5%261296%5Cend%7Barray%7D%5Cright%5D)
It is easier to notice that 16 and 125 result from the second power of 4 and the third of 5, respectively, which are one number below their respective position. That is why we can deduce that the base of the power is n+1.
For n=2, the base n+1 results in 3, which matches the nth term for n=2. Since 3 is the result of 3 to the power of 1, 16 is 4 to the power of 2, and 125 is 5 to the power of 3, all the powers are one number behind n, so the power is given by n-1, giving the equation:

Step-by-step explanation:
B) perpendicular and intersecting
Answer:
no
Step-by-step explanation:
The correct explanation is A
= 
Thus
× 
= 2.3 × 
= 2.3 × 