2 years ago

HELP PLEASE HURRY!!

Mathematics

1 answer:

nikklg [1K]2 years ago

6 0

The second one !!!

I’m pretty sure

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Simplify the radical expression below square root of 5/64

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Step-by-step explanation:

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2 years ago

Find the exact value of cot(15degrees) using half angle formulas?

liubo4ka [24]

Double angle (or half angle, depending how you look at it) identities:

$\cos^2\dfrac x2=\dfrac{1+\cos x}2$

$\sin^2\dfrac x2=\dfrac{1-\cos x}2$

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So we have

$\cot^215^\circ=\dfrac{1+\cos30^\circ}{1-\cos30^\circ}=\dfrac{1+\frac{\sqrt3}2}{1-\frac{\sqrt3}2}$

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Note that when taking the square root, we should take into account that that could yield two possible solutions, but we know $\cos15^\circ>0$ and $\sin15^\circ>0$ , so it's also the case that $\cot15^\circ>0$ .

Also, the reason we have equality in the last step can be explained like so:

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3 years ago

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Hatshy [7]

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y = tan(60) * 5
and you know tan(60) = √3
so
y = 5√3

answer
5√3 (exact value)

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