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vitfil [10]
3 years ago
9

Kelly had $25 in her purse and Dante has d dollars in his wallet which algebraic expression represents the total amount that jel

ly and Dante have
Mathematics
1 answer:
olga_2 [115]3 years ago
7 0

25+D=total amount     hope this helps :)

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Hollis put a layer of boxes in the bottom of a container. Each box has a volume of 1 cubic foot. The base layer of boxes in the
nignag [31]

Answer:

288 ft³

Step-by-step explanation:

Given that

The volume of each box is 1 cubic foot

And, Hollies required 8 of these layers

Now based on the above information

We assume that the dimension of the base layer is 6 by 6

So, the volume of the container is

= Length × Width × Height

where,

Length = 6 ft

Width = 6 ft

And, Height = 8 ft

So,

= 6 ft × 6 ft × 8 ft

= 288 ft³

3 0
3 years ago
Please help
Vlada [557]

We know that

When we have

f(x)=ax^2 +bx+c

Here ,

a is the leading coefficient

c is the constant term

so, we can compare it with

f(x)=5x^2-7x+6

so, we get

a=5,c=6

so,

leading coefficient is 5

constant term is 6......................Answer

4 0
3 years ago
Instructions: Find the measure of the indicated angle to the nearest
SVETLANKA909090 [29]

To find the indicated angle, we can use one of the three main trigonometric functions: sine, cosine, or tangent.

Remember: SOH-CAH-TOA

Looking from the angle, we know the adjacent side and the hypotenuse. Therefore, we should use cosine to solve.

cos(x) = 12/36

x = cos^-1(12/36)

x = 71 degrees

Hope this helps!

6 0
2 years ago
If 30% of John's photographs were perfect, but 210 photographs were not perfect, then how many photographs were there in all?
anyanavicka [17]
If 30% were perfect, 70% were not perfect.  So we know that 70% of the total number of photographs is 210.

p(70/100)=210  multiply both sides by 100

70p=21000  divide both sides by 70

p=300

So there are 300 photographs in all.
3 0
3 years ago
Yes I am kinda dumb lol
Rama09 [41]

Answer:

I think it is A

Step-by-step explanation:

just trying to help

5 0
2 years ago
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