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ladessa [460]
2 years ago
14

Which term refers to a shorthand method for identifying network and host bits in an ip address?

Computers and Technology
1 answer:
zloy xaker [14]2 years ago
7 0

A CIDR Notation is known as the term that refers to a shorthand method for identifying network and host bits in an ip address.

<h3>What is CIDR Notation?</h3>

This is known to be a term that was devised in 1993 by the IETF. The  CIDR is said to be a  shorthand method for knowing network and host bits in an IP address.

Therefore, one can say that A CIDR Notation is known as the term that refers to a shorthand method for identifying network and host bits in an ip address.

Learn more about CIDR Notation from

brainly.com/question/14985928

#SPJ12

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Describe how to deploy a website and make it as secure as possible while reducing its resources used
erastova [34]

Answer:

Explanation:

in order to deploy a website, you use these 5 steps, the first step is the preparation step, the second step is to set up DNS record, in step 3 a live testing is set up, in step 4 you set up email accounts while in step 5, you back up and now go live.

in order to secure your website from any threat, malware it hacker it it is necessary to use HTTPS. HTTPS, protects the websites integrity. it also provides data protection as data encryption provides such security. parameterized queries can also be used.

5 0
3 years ago
Develop a plan to design and finally implement a set of functions using C++ that would implement the IEEE standard. Phase 1 will
AnnZ [28]

Answer:

See explaination code

Explanation:

#include<iostream>

#include<math.h>

using namespace std;

typedef union {

float number;

struct

{

// Order is important.

// Here the members of the union data structure

// use the same memory (32 bits).

// The ordering is taken

// from the LSB to the MSB.

unsigned int mantissa : 23;

unsigned int exponent : 8;

unsigned int sign : 1;

} Raw;

} MyFloat;

void printBinary(int n, int i)

{

// Prints the binary representation

// of a number n up to i-bits.

int k;

for (k = i - 1; k >= 0; k--) {

if ((n >> k) & 1)

cout << "1";

else

cout << "0";

}

}

void decToHex(int n){

// char array to store hexadecimal number

char hexaDeciNum[100];

// counter for hexadecimal number array

int i = 0;

while(n!=0)

{

// temporary variable to store remainder

int temp = 0;

// storing remainder in temp variable.

temp = n % 16;

// check if temp < 10

if(temp < 10)

{

hexaDeciNum[i] = temp + 48;

i++;

}

else

{

hexaDeciNum[i] = temp + 55;

i++;

}

n = n/16;

}

// printing hexadecimal number array in reverse order

for(int j=i-1; j>=0; j--)

cout << hexaDeciNum[j];

}

void floatBinary(float f){

long double binaryTotal, binaryFrac = 0.0, frac, fracFractor = 0.1;

long int integer, binaryInt = 0;

long int p = 0, rem, temp;

//separate the integer part from the input floating number

integer = (int)f;

//separate the fractional part from the input floating number

frac = f - integer;

//loop to convert integer part to binary

while (integer != 0) {

rem = integer % 2;

binaryInt = binaryInt + rem *pow(10, p);

integer = integer / 2;

p++;

}

//loop to convert fractional part to binary

while (frac != 0) {

frac = frac * 2;

temp = frac;

binaryFrac = binaryFrac + fracFractor * temp;

if (temp == 1)

frac = frac - temp;

fracFractor = fracFractor / 10;

}

cout << binaryInt + binaryFrac;

}

int findDecimal(float number){

int nfloor = number;

float nfloat = number - nfloor;

int nfloatfloor;

do {

nfloat *= 10;

nfloatfloor = nfloat;

} while (nfloat > nfloatfloor);

return nfloatfloor;

}

void first(float number){

if(number < 0)

cout << "SIGN BIT IS (1) SINCE NUMBER IS NEGATIVE" << endl;

else

cout << "SIGN BIT IS (0) SINCE NUMBER IS POSITIVE" << endl;

}

void second(float number){

cout << "INTEGER PART IN BASE-10:" << int(number) << " AND IN BINARY:";

printBinary(int(number),16);

cout << endl;

}

void third(float number){

cout << "DECIMAL PART IN BASE-10:" << findDecimal(number) << " AND IN BINARY:";

printBinary(findDecimal(number),16);

cout << endl;

}

void fourth(float number){

cout << "ENTERED NUMBER IN BASE-10:" << number << " AND IN BINARY:";

floatBinary(number);

cout << endl;

}

void fifth(MyFloat myfloat){

cout << "MANTISA IN BINARY:";

printBinary(myfloat.Raw.mantissa,32);

}

void sixth(MyFloat myfloat){

cout << "EXPONENT IN BASE-10:" << myfloat.Raw.exponent << " AND IN BINARY:";

printBinary(myfloat.Raw.exponent,8);

cout << endl;

}

void seventh(MyFloat myfloat){

cout << myfloat.Raw.sign << " | ";

printBinary(myfloat.Raw.exponent,8);

cout << " | ";

printBinary(myfloat.Raw.mantissa,32);

cout << endl;

}

void eigth(MyFloat myfloat){

cout << myfloat.Raw.sign << " | ";

decToHex(myfloat.Raw.exponent);

cout << " | ";

decToHex(myfloat.Raw.mantissa);

cout << endl;

}

int main(){

float number;

cout << "PLEASE ENTER A NUMBER TO DISPLAY THE IEEE 754 FLOATING POINT OPTIONS" << endl;

cin >> number;

MyFloat myfloat;

myfloat.number = number;

cout << "PLEASE CHOOSE ONE OF THE FOLLOWING OPERATIONS" << endl;

cout << " 1. DISPLAY THE SIGN BIT VALUE" << endl;

cout << " 2. DISPLAY THE INTEER PART IN BOTH BASE-10 AND CINARY FORMATS" << endl;

cout << " 3. DISPLAY THE DECIMAL PART IN BOTH BASE-10 AND BINARY FORMATS" << endl;

cout << " 4. DISPLAY THE NUMBER ENTERED IN BOTH BASE-10 AND BINARY FORMATS" << endl;

cout << " 5. DISPLAY THE MANTISA IN BINARY FORMATS" << endl;

cout << " 6. DISPLAY THE EXPONENT IN BORH BASEE-10 AND BINARY FORMATS" << endl;

cout << " 7. DISPLAY THE IEEE 754 SINGLE PRECISION BINARY LAYOUT" << endl;

cout << " 8. DISPLAY THE IEEE 754 SINGLE PRECISION BINARY LAYOUT" << endl;

int choice;

cin >> choice;

switch(choice){

case 1:first(number);

break;

case 2:second(number);

break;

case 3:third(number);

break;

case 4:fourth(number);

break;

case 5:fifth(myfloat);

break;

case 6:sixth(myfloat);

break;

case 7:seventh(myfloat);

break;

case 8:eigth(myfloat);

break;

default:cout << "ENTER VALID CHOICE" << endl;

}

}

Refer to attachment please for onscreen look.

6 0
3 years ago
You're installing two new hard drives into your network attached storage device. Your director asks that they be put into a RAID
bekas [8.4K]

Answer:

d. RAID 6

Explanation:

RAID is a data storage technology that combines multiple physical disk drive components into a single logical unit. The functions of RAID is to provide performance and redundancy.

RAID 0 provides data stripping but it does not offer data stripping.

RAID 1 increases performance to about 2x but it limits the disk capacity to about 50%

RAID 5 provides redundancy and increased perfomance but it is limited to small disk drive.

RAID 6 also provides redundancy but it slows performance

RAID 10 increases performance and data protection.

RAID 6 is the best drive that offers redundancy over performance.

8 0
3 years ago
ก
Harrizon [31]

Answer:

Rubies are used in electronics.

 

Please select the best answer from the choices provided

T

Explanation:

6 0
3 years ago
Read 2 more answers
Which of the following functions grows at a faster rate than the rest? (Points : 6)
ehidna [41]

Answer:

n2.

Explanation:

The function with the time complexity of n2 is the fastest growing function is in terms of square.As n increases the time complexity will grow very rapidly.

n=1   n2=1

n=2   n2=4

n=3   n2=9

n=4   n2=16

n=5   n2=25.

The slowest growing function among them is log n then n and then n log n.

n log n is better than n2.

4 0
3 years ago
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