B........................
Answer:
Approximately, the 90% confidence interval for the students' mean IQ score is between 129.045 - 130.956
Step-by-step explanation:
The formula to use to solve this question is called the Confidence Interval formula.
Confidence interval =
x ± z × ( σ/ (√n) )
Where:
x = the sample mean = 130
z = the z-value for 90% confidence = 1.645
σ = standard deviation = 7
n = sample size = 145
130 ± 1.645 × (7/√145)
130 ± 0.9562687005
130 - 0.9562687005 = 129.0437313
130 + 0.9562687005 = 130.9562687005
Therefore, approximately, the 90% confidence interval for the students' mean IQ score is between 129.045 - 130.956
14, B. I hope that helps! :)
Answer:
Step-by-step explanation:
using the slope-intercept formula, u have this so far as an equation (just knowing the slope): 
To find the y-intercept, substitute in the values of the coordinates given to solve for b:
so u can just put 8 into your slope-intercept formula () and that's it! hope this helps!
