Which step should be used to prove that point P is equidistant from points R and Q

Mathematics

1 answer:

nydimaria [60]3 years ago

6 0

Step-by-step explanation:

1. If any one side and any one common angle are equal in triangles PQR and PRS, then their corresponding sides are also equal.

2. If two sides and one included angle are equal in triangles PQS and PRS, then their third sides are equal.

3. In triangles PQR and PQS, if one side and one angle are equal, then their corresponding sides and angles are also equal.

4. In triangles PRS and PQS, all three angles are equal.

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Prove 2^n > n for all n equal to or greater than 1. I mostly need help with how to solve the problem when it is greater than

noname [10]

If $n$ is an integer, you can use induction. First show the inequality holds for $n=1$ . You have $2^1=2>1$ , which is true.

Now assume this holds in general for $n=k$ , i.e. that $2^k>k$ . We want to prove the statement then must hold for $n=k+1$ .

Because $2^k>k$ , you have

$2^{k+1}=2\times2^k>2k$

and this must be greater than $k+1$ for the statement to be true, so we require

$2k>k+1$

for $k>1$ . Well this is obviously true, because solving the inequality gives $3k>1\implies k>\dfrac13$ . So you're done.

If you $n$ is any real number, you can use derivatives to show that $2^n$ increases monotonically and faster than $n$ .

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2 years ago

f(x)= 1/x, vertically stretched by a factor of 7, reflected in the y-axis, translated 5 units to the right, and translated 3 uni

Harman [31]

Answer:

-7/(x-5) - 3

Step-by-step explanation:

First off, to reflect an equation in the y axis, just multiply by -1. Now that it is reflected, to stretch an equation by a factor of 7, multiply it by 7. Now we have -7/x.

Then, to move an equation down by 3 units, simply subtract it by 3. Now we have -7/x - 3.

Lastly, since you want to translate it 5 units to the left, you want the equation to be undefined at x = 5 (because originally it is undefined at x = 0). To do that, set the denominator to x - 5. We arrive at our answer: -7/(x-5) - 3.

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2 years ago

Itskorey please help me im stuck again<br><br> one hundred seventy thousands

vlada-n [284]

17000
This time its thousands not hundreds, so you do 17 plus 000 wich would be thousands, like this
one thousand
1
thousand
000
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2 years ago

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weeeeeb [17]

i y vino the answer is 60° i hope so

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